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NCERT Exemplar · Q19

Q.An unsymmetrical double convex thin lens forms the image of a point object on its axis. Will the position of the image change if the lens is reversed?

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No. A thin lens has the same focal length whichever face points toward the object, so for a given object distance the image forms in exactly the same place.

Why the focal length is unchanged on reversal

For a thin lens in air the lens maker's formula is

1f=(μ−1)(1R1−1R2)\frac{1}{f} = (\mu - 1)\left(\frac{1}{R_1} - \frac{1}{R_2}\right)

Take the original orientation of the (unsymmetrical) double convex lens with first-surface radius +a+a (centre of curvature on the outgoing side) and second-surface radius −b-b:

1f=(μ−1)(1a−1−b)=(μ−1)(1a+1b)\frac{1}{f} = (\mu - 1)\left(\frac{1}{a} - \frac{1}{-b}\right) = (\mu - 1)\left(\frac{1}{a} + \frac{1}{b}\right)

Now reverse the lens. The face of magnitude bb meets the light first (radius +b+b), and the face of magnitude aa becomes the second surface (radius −a-a):

1f′=(μ−1)(1b−1−a)=(μ−1)(1b+1a)\frac{1}{f'} = (\mu - 1)\left(\frac{1}{b} - \frac{1}{-a}\right) = (\mu - 1)\left(\frac{1}{b} + \frac{1}{a}\right) …

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