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Q.Show the σ (sigma) and π (pi) bonds present in the following molecules: C6H6, C6H12, CH2Cl2, CH2=C=CH2 OR Write the IUPAC names of the following:

(a) [structural formula: CH3-C(=O)-CH3, drawn with the C=O bond shown vertically below the central carbon]
(b) [structural formula: a six-membered ring bearing a -Cl substituent (bond from the upper area) and an -OH substituent (bond from the lower-right)]
Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2023Subjective· 2mImportance★★★★★
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Answering the primary part of this OR question: counting each molecule's sigma and pi bonds gives C6H6 = 12σ+3π, C6H12 = 18σ+0π, CH2Cl2 = 4σ+0π, and CH2=C=CH2 = 6σ+2π. (The OR alternative asked for IUPAC names from a hand-drawn figure; see the note on that below.)

Rule used throughout: every single bond is 1 sigma bond; every double bond is 1 sigma + 1 pi bond; every C-H bond is a sigma bond.

  1. C6H6 (benzene, planar 6-membered ring with alternating double bonds in the Kekulé structure): 6 C-C sigma bonds forming the ring + 6 C-H sigma bonds (one per carbon) = 12 sigma bonds. The ring's 3 formal C=C double bonds contribute 3 pi bonds (these are actually delocalised over the ring, but the bond count is still 3 pi bonds' worth of electron density).

    Total: 12σ, 3π.

  2. C6H12 (cyclohexane, saturated 6-membered ring, all single bonds): 6 C-C sigma bonds (ring) + 12 C-H sigma bonds (2 H per carbon × 6 carbons) = 18 sigma bonds, and no pi bonds since the ring is fully saturated.

    Total: 18σ, 0π.

  3. CH2Cl2 (dichloromethane, a single sp3 carbon bonded to 2 H and 2 Cl): 2 C-H sigma bonds + 2 C-Cl sigma bonds = 4 sigma bonds total, and no pi bonds (no multiple bonds present).

    Total: 4σ, 0π.

    …

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