Skip to content
Problems · Problem 2.18

Q.Using s, p, d, f notations, describe the orbital with the following quantum numbers

(a) n = 2, l = 1,
(b) n = 4, l = 0,
(c) n = 5, l = 3,
(d) n = 3, l = 2.
Rajasthan RbseTextbookSubjective· 2mImportance★★★★★est
13% · 18/140 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The quantum numbers (n,l)(n, l) map directly to orbital notations: l=0l=0 is s, l=1l=1 is p, l=2l=2 is d, l=3l=3 is f. The answers are: (a) 2p,

(b) 4s,

(c) 5f,

(d) 3d.

The question asks you to translate a pair of quantum numbers — principal quantum number nn and azimuthal quantum number ll — into the familiar s, p, d, f notation. This is a fundamental skill in atomic structure, and it rests on understanding how the value of ll determines the shape (subshell) of an orbital.

Why this mapping exists.

The quantum number ll can take integer values from 00 to n−1n-1. Each value of ll corresponds to a specific subshell letter:

llLetterShape description
0sSpherical
1pDumbbell
2dCloverleaf
3fComplex

The orbital notation is simply nn followed by the letter. For example, n=2n=2, l=1l=1 becomes 2p.

Now let’s apply this to each case.

  1. Case (a): n=2n = 2, l=1l = 1

    l=1l=1 means the subshell is p. So the orbital is written as 2p.

  2. Case (b): n=4n = 4, l=0l = 0

    l=0l=0 means the subshell is s. So the orbital is 4s.

  3. Case (c): n=5n = 5, l=3l = 3

    l=3l=3 means the subshell is f. So the orbital is 5f. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.