Skip to content
Question of 94

Q.Represent the inequality x+y<5x+y<5 graphically on the two-dimensional plane.

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2023Subjective· 3mImportance★★★★★
0% · 0/94 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The solution of x+y<5x+y<5 is the open half-plane on the origin's side of the dashed line x+y=5x+y=5.

Step 1 — Draw the boundary line. Consider the equation x+y=5x+y=5. It passes through, e.g., (5,0)(5,0) and (0,5)(0,5). Draw this line dashed (not solid), because the inequality is strict (<<, not ≤\le), so points exactly on the line are NOT part of the solution.

Step 2 — Test a point not on the line. Use the origin (0,0)(0,0) as a convenient test point (since it is not on the line):

0+0=0<5✓ true0+0 = 0 < 5 \quad \checkmark \text{ true}

Since the origin satisfies the inequality, the origin's side of the line is the solution region.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.