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Exercise 6.1 · Q5

Q.A coin is tossed 3 times and the outcomes are recorded. How many possible outcomes are there?

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Each toss has 2 independent outcomes, and with 3 tosses we multiply: 2×2×2=82 \times 2 \times 2 = 8 possible outcomes.

When you toss a coin, you get either heads (H) or tails (T) — two possibilities. The question asks: if we repeat this three times and record the sequence, how many different sequences can we get?

The key insight is the Fundamental Counting Principle: when you perform a sequence of independent choices, the total number of outcomes is the product of the number of choices at each stage. Each coin toss is independent — what happens on the second toss doesn't depend on the first, and so on.

Let's count systematically:

  1. First toss: You have 2 choices (H or T).

  2. Second toss: Regardless of what happened in the first toss, you again have 2 choices (H or T).

  3. Third toss: Once more, independent of everything before, you have 2 choices (H or T).

By the counting principle, the total number of outcomes is:

2×2×2=23=82 \times 2 \times 2 = 2^3 = 8

If you want to see them all explicitly, here's the complete list of sequences:

| Outcome 1 | Outcome 2 | Outcome 3 | Outcome 4 | Outcome 5 | Outcome 6 | Outcome 7 | Outcome 8 | …

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