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Exercise 2.2 · Q6

Q.Determine the domain and range of the relation RR defined by R={(x,x+5):x∈{0,1,2,3,4,5}}R = \{(x, x + 5) : x \in \{0, 1, 2, 3, 4, 5\}\}.

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A relation is simply a set of ordered pairs; the domain collects all first coordinates and the range collects all second coordinates. Here the domain is {0,1,2,3,4,5}\{0, 1, 2, 3, 4, 5\} and the range is {5,6,7,8,9,10}\{5, 6, 7, 8, 9, 10\}.

Understanding Relations as Sets of Ordered Pairs

A relation RR from a set AA to a set BB is nothing more than a subset of A×BA \times B—a collection of ordered pairs (x,y)(x, y) where x∈Ax \in A and y∈By \in B. The rule (x,x+5)(x, x+5) tells us how to build each pair: take an element xx from the given set and pair it with x+5x+5.

The domain of RR is the set of all first components (the xx-values that actually appear in the relation), and the range is the set of all second components (the yy-values that actually appear).

Step-by-Step Construction

1. List all ordered pairs in the relation

We substitute each element from {0,1,2,3,4,5}\{0, 1, 2, 3, 4, 5\} into the rule (x,x+5)(x, x+5):

  • When x=0x = 0: (0,0+5)=(0,5)(0, 0+5) = (0, 5)
  • When x=1x = 1: (1,1+5)=(1,6)(1, 1+5) = (1, 6)
  • When x=2x = 2: (2,2+5)=(2,7)(2, 2+5) = (2, 7)
  • When x=3x = 3: (3,3+5)=(3,8)(3, 3+5) = (3, 8)
  • When x=4x = 4: (4,4+5)=(4,9)(4, 4+5) = (4, 9)
  • When x=5x = 5: (5,5+5)=(5,10)(5, 5+5) = (5, 10)

So the relation is:

R={(0,5),(1,6),(2,7),(3,8),(4,9),(5,10)}R = \{(0, 5), (1, 6), (2, 7), (3, 8), (4, 9), (5, 10)\}

2. Extract the domain

The domain consists of all first coordinates from the ordered pairs in RR. Reading off the first element of each pair:

Domain={0,1,2,3,4,5}\text{Domain} = \{0, 1, 2, 3, 4, 5\} …

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