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Miscellaneous Examples · Example 13

Q.The variance of 20 observations is 5. If each observation is multiplied by 2, find the new variance of the resulting observations.

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✓ Free question

When every observation is multiplied by a constant kk, the variance gets multiplied by k2k^2. Here, multiplying by 2 scales the variance by 22=42^2 = 4, giving a new variance of 20.

Why Scaling Affects Variance

Variance measures the spread of data around the mean—how far observations typically deviate from their average. When you multiply every observation by a constant, you're stretching (or compressing) the entire dataset uniformly. The mean shifts by the same factor, but the distances between points and the mean also scale by that factor.

Since variance involves squared deviations, and each deviation gets multiplied by kk, the variance itself gets multiplied by k2k^2. This is a fundamental property of variance under linear transformations.

Step-by-Step Solution

  1. Recall the variance formula For observations x1,x2,…,xnx_1, x_2, \ldots, x_n with mean xˉ\bar{x}, the variance is:

σ2=1n∑i=1n(xi−xˉ)2\sigma^2 = \frac{1}{n} \sum_{i=1}^{n} (x_i - \bar{x})^2

We're told that for our 20 observations, σ2=5\sigma^2 = 5.

  1. Define the new observations

    Let the new observations be yi=2xiy_i = 2x_i for each i=1,2,…,20i = 1, 2, \ldots, 20.

  2. Find the new mean

    The mean of the new observations is:

yˉ=120∑i=120yi=120∑i=1202xi=2⋅120∑i=120xi=2xˉ\bar{y} = \frac{1}{20} \sum_{i=1}^{20} y_i = \frac{1}{20} \sum_{i=1}^{20} 2x_i = 2 \cdot \frac{1}{20} \sum_{i=1}^{20} x_i = 2\bar{x}

The mean also gets multiplied by 2.

  1. Calculate the new variance The variance of the new observations is:

σy2=120∑i=120(yi−yˉ)2=120∑i=120(2xi−2xˉ)2\sigma_y^2 = \frac{1}{20} \sum_{i=1}^{20} (y_i - \bar{y})^2 = \frac{1}{20} \sum_{i=1}^{20} (2x_i - 2\bar{x})^2

Factor out the 2:

σy2=120∑i=120[2(xi−xˉ)]2=120∑i=1204(xi−xˉ)2\sigma_y^2 = \frac{1}{20} \sum_{i=1}^{20} [2(x_i - \bar{x})]^2 = \frac{1}{20} \sum_{i=1}^{20} 4(x_i - \bar{x})^2

σy2=4⋅120∑i=120(xi−xˉ)2=4σ2\sigma_y^2 = 4 \cdot \frac{1}{20} \sum_{i=1}^{20} (x_i - \bar{x})^2 = 4 \sigma^2

  1. Substitute the original variance Since σ2=5\sigma^2 = 5:

σy2=4×5=20\sigma_y^2 = 4 \times 5 = 20

If yi=kxi for all i, then Var(Y)=k2⋅Var(X)\text{If } y_i = kx_i \text{ for all } i, \text{ then } \text{Var}(Y) = k^2 \cdot \text{Var}(X)

Tip

The number of observations (20 in this case) doesn't affect the scaling rule—variance always scales by k2k^2 regardless of sample size.

✓Final answer

The new variance of the resulting observations is 20\boxed{20}.

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