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Exercise 9.2 · Q11

Q.Find the equation of a line that cuts off equal intercepts on the coordinate axes and passes through the point (2,3)(2, 3).

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A line with equal intercepts on both axes has the form x+y=ax + y = a; substituting (2,3)(2,3) gives a=5a=5, so the equation is x+y=5x + y = 5.

Understanding Equal Intercepts

When a line cuts off equal intercepts on the coordinate axes, it means the xx-intercept and yy-intercept have the same absolute value. Picture this: if the line meets the xx-axis at (a,0)(a, 0) and the yy-axis at (0,b)(0, b), then "equal intercepts" means a=ba = b.

The intercept form of a line is:

xa+yb=1\frac{x}{a} + \frac{y}{b} = 1

where aa is the xx-intercept and bb is the yy-intercept. If a=ba = b, this simplifies beautifully:

xa+ya=1\frac{x}{a} + \frac{y}{a} = 1

Multiply through by aa:

x+y=ax + y = a

This is the standard form for any line with equal intercepts. The line makes a 45°45° angle with the positive xx-axis (slope =−1= -1), cutting both axes at the same distance from the origin.

x+y=ax + y = a

where aa is the common intercept value.

Finding the Specific Line

Now we use the constraint that the line passes through (2,3)(2, 3).

  1. Substitute the point into the general form. Since (2,3)(2, 3) lies on the line x+y=ax + y = a, we have:

2+3=a2 + 3 = a

a=5a = 5

  1. Write the final equation. …

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