NCERT Exemplar · Q27
Q.According to Stefan's law of radiation, a black body radiates energy from its unit surface area every second where is the surface temperature of the black body and W/mK is known as Stefan's constant. A nuclear weapon may be thought of as a ball of radius 0.5 m. When detonated, it reaches temperature of K and can be treated as a black body.
(a) Estimate the power it radiates.
(b) If surrounding has water at C, how much water can 10% of the energy produced evaporate in 1 s?
(c) If all this energy is in the form of radiation, corresponding momentum is . How much momentum per unit time does it impart on unit area at a distance of 1 km?
Rajasthan RbseLong· 5mImportance★★★★★est
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Start your 14-day free trial to unlock the full solution →Stefan's law gives the fireball's radiated power as .
- W.
- Using 10% of one second's energy to first heat then vaporise water gives a mass evaporated of kg.
- Spreading this power over a sphere of radius 1 km and dividing by gives a radiation pressure of about 47.2 Pa.
(a) Power radiated
The fireball (radius m) is treated as a black body, so its whole surface radiates at rate per unit area. Surface area:
At K:
(b) Water evaporated using 10% of the energy in 1 s
Energy radiated in 1 s is J, so of it is
To evaporate water starting at C, it must first be heated to C ( K) and then vaporised at C. Per kilogram:
Mass evaporated:
(c) Momentum per unit time per unit area at 1 km
Radiation carries momentum , so momentum per unit time (force) is . Spread over a sphere of radius m, the intensity is
and the momentum delivered per unit time per unit area (radiation pressure on an absorbing surface) is …
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