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Q.A Carnot's engine absorbs 100 calorie of heat from source at 400K and rejects 80 calorie of heat to the sink. Calculate the temperature of sink and efficiency of engine.

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2017Subjective· 3mImportance★★★★★
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Using Q2/Q1 = T2/T1 for a Carnot engine, the sink temperature works out to 320 K and the efficiency to 20%.

Given: Heat absorbed from source, Q1 = 100 cal; heat rejected to sink, Q2 = 80 cal; source temperature, T1 = 400 K.

For a Carnot (reversible) engine, the ratio of heat exchanged equals the ratio of the corresponding absolute temperatures:

Q2 / Q1 = T2 / T1

Solving for the sink temperature T2:

T2 = T1 × (Q2 / Q1) = 400 × (80/100) = 400 × 0.8 = 320 K

Efficiency of the Carnot engine: …

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