Q.A physical quantity X is related to four measurable quantities a, b, c and d as follows: X=a2b3c5/2d−2. The percentage error in the measurement of a, b, c and d are 1%, 2%, 3% and 4%, respectively. What is the percentage error in quantity X? If the value of X calculated on the basis of the above relation is 2.763, to what value should you round off the result.
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Significant Figures Calculation
Significant Figures: The Art of Honest Measurement
Imagine you're measuring the length of a table with a ruler that has marks every millimeter. You see the table edge falls somewhere between 152.3 cm and 152.4 cm. You estimate it as 152.35 cm. But here's the truth: you're certain about 152.3, pretty sure about the 0.05, and guessing about anything beyond that. Significant figures are simply a way to communicate how much of that number you actually know.
The Core Idea
Every measurement has uncertainty. Significant figures (or "sig figs") are the digits in a number that carry meaningful information about its precision. They include all the digits you're sure of, plus one more that you estimate.
A digit is "significant" if removing it would change the precision of the measurement. Zeros can be tricky — they might just be placeholders.
The Rules (Memorize These)
1. Non-zero digits are always significant
123.45 has 5 sig figs. Simple.
2. Zeros between non-zero digits are significant
1002 has 4 sig figs. The zeros are "sandwiched" — they're part of the measurement.
3. Leading zeros are never significant
0.00123 has 3 sig figs. Those zeros just tell you where the decimal point is.
4. Trailing zeros are significant only if there's a decimal point
- 1200 has 2 sig figs (no decimal — zeros are placeholders)
- 1200. has 4 sig figs (decimal tells us those zeros were measured)
- 1200.0 has 5 sig figs
5. Exact numbers have infinite sig figs
If you count 5 apples, that's exactly 5 — no uncertainty. Conversion factors like 1 m=100 cm are exact by definition.
When in doubt, write the number in scientific notation. 1.20×103 clearly has 3 sig figs, while 1.2×103 has 2.
Why This Matters: Calculations
When you multiply or add measurements, the uncertainty propagates. You can't claim more precision than your least precise measurement.
Multiplication and Division
The result should have the same number of sig figs as the measurement with the fewest sig figs.
3.14×2.5=7.85 but you report 7.9 (2 sig figs, because 2.5 has only 2)
Addition and Subtraction
The result should have the same decimal places as the measurement with the fewest decimal places.
12.11+18.0=30.11 but you report 30.1 (one decimal place, because 18.0 has one) …
Why this formula?
Significant Figures: Why the Rules Work
Let’s start with the core idea: significant figures (sig figs) are a way to honestly report how precise a measurement is. The rules for addition/subtraction and multiplication/division aren’t arbitrary — they come directly from how uncertainty propagates through calculations.
1. The Fundamental Idea: Uncertainty is the Key
Every measurement has an uncertainty (error). When we say a length is 12.3 cm, we mean:
- The true value lies somewhere between 12.25 cm and 12.35 cm (assuming ±0.05 cm uncertainty).
- The last digit (3) is uncertain; the digits before it (1 and 2) are certain.
Why this matters: When we combine measurements, the uncertainty in the result depends on the uncertainties of the inputs. Sig fig rules are a shortcut for this uncertainty propagation.
2. Rule for Addition and Subtraction
Statement: The result should have the same number of decimal places as the measurement with the fewest decimal places.
Example:
12.3+4.56=16.86 → round to 16.9 (one decimal place, like 12.3)
Why this holds
Consider two measurements:
- A=12.3±0.05 (uncertainty in the tenths place)
- B=4.56±0.005 (uncertainty in the hundredths place)
When we add:
- Certain digits: 12.3 has certainty up to the tenths place. 4.56 has certainty up to the hundredths place.
- The weaker link: The tenths place of A is uncertain. So in the sum, the hundredths place (from B) is meaningless — because we don’t even know the tenths place of A exactly.
Mathematically, the absolute uncertainty in the sum is:
Δ(A+B)=(ΔA)2+(ΔB)2≈0.052+0.0052≈0.0502
This uncertainty is ~0.05, which affects the tenths place. So reporting the hundredths place is false precision.
Key takeaway: The result’s last significant digit is in the same decimal place as the least precise measurement’s last digit.
3. Rule for Multiplication and Division
Statement: The result should have the same number of significant figures as the measurement with the fewest significant figures.
Example:
12.3×4.56=56.088 → round to 56.1 (three sig figs, like both inputs)
Why this holds
Let’s use relative uncertainty (percentage error):
- A=12.3±0.05 → relative uncertainty = 12.30.05≈0.00407 (0.407%)
- B=4.56±0.005 → relative uncertainty = 4.560.005≈0.00110 (0.110%)
For multiplication, relative uncertainties add (approximately):
A×BΔ(A×B)≈(AΔA)2+(BΔB)2
Plugging in:
≈0.004072+0.001102≈0.00422 (0.422%)
Now, the absolute uncertainty in the product:
Δ(A×B)≈0.00422×(12.3×4.56)≈0.00422×56.088≈0.237
This uncertainty (~0.2) affects the tenths place of the result. So the result 56.088 has uncertainty in the first decimal — meaning only three digits (5, 6, and the uncertain 1) are meaningful. That’s three sig figs, matching the input with fewer sig figs (both have three here).
Key takeaway: The number of sig figs in the result is limited by the least precise measurement’s number of sig figs, because relative uncertainty is dominated by the measurement with the largest relative error.
4. Why These Rules Are Different …
XΔX×100=2(1%)+3(2%)+25(3%)+2(4%)=2+6+7.5+8=23.5%
Absolute uncertainty on X=2.763: ΔX=0.235×2.763≈0.65 — comparable to the ones digit, so only the whole-number part of X …
The percentage error in X=a2b3c5/2d−2 works out to 23.5%; since this makes the absolute uncertainty on X=2.763 comparable to its ones digit, the value should be rounded to X≈3.
Percentage error in a power-law combination
For X=ambncpdq, errors combine as:
XΔX×100=∣m∣(aΔa×100)+∣n∣(bΔb×100)+∣p∣(cΔc×100)+∣q∣(dΔd×100)
Here X=a2b3c5/2d−2, so m=2, n=3, p=5/2, ∣q∣=2, and the given percentage errors are 1%, 2%, 3%, 4% respectively.
Computing the total
XΔX×100=2(1%)+3(2%)+25(3%)+2(4%)=2%+6%+7.5%+8%=23.5%
Deciding how to round X = 2.763
The percentage error tells us the absolute uncertainty on the given value X=2.763:
ΔX=10023.5×2.763≈0.649 …
Method: Propagation of Errors (for products and powers)
This method uses the rule that for a quantity expressed as a product of powers, the relative error adds up with the powers as coefficients.
Steps
1. Write the general formula for relative error
If
X=ambncpdq
then the relative error in X is:
XΔX=∣m∣aΔa+∣n∣bΔb+∣p∣cΔc+∣q∣dΔd
Here, the signs of exponents don’t matter for error addition — we take absolute values of the powers.
2. Identify the powers and given percentage errors
From X=a2b3c5/2d−2:
- Power of a: m=2
- Power of b: n=3
- Power of c: p=5/2=2.5
- Power of d: q=−2 → use ∣q∣=2
Given percentage errors:
- aΔa×100=1%
- bΔb×100=2%
- cΔc×100=3%
- dΔd×100=4%
3. Compute percentage error in X …
🔍 Mistake 1: Forgetting the power rule for errors
The mistake:
Students often write the percentage error in X as just the sum of the percentage errors in a, b, c, and d:
XΔX×100=1%+2%+3%+4%=10%
Why it’s wrong:
The formula for error propagation in multiplication/division with powers is:
Percentage error in X = sum of (power × percentage error in each quantity)
So for X=a2b3c5/2d−2, the correct expression is:
XΔX×100=2(1%)+3(2%)+25(3%)+2(4%)
How to avoid:
Always multiply each percentage error by its exponent (absolute value of the power) before adding. The sign of the exponent doesn’t matter — errors always add.
🔍 Mistake 2: Using the wrong sign for d−2
The mistake:
Some students treat d−2 as subtracting the error:
XΔX×100=⋯−2(4%)
Why it’s wrong:
Errors always add in quadrature (or directly in this simplified method). The negative exponent means d is in the denominator, but the uncertainty still adds to the total error.
How to avoid:
Remember: for X=ambn,
XΔX=∣m∣aΔa+∣n∣bΔb
Take absolute values of the powers.
🔍 Mistake 3: Arithmetic slip with 25×3%
The mistake:
Students often compute 25×3% incorrectly — either as 7.5% (correct) or mistakenly as 215%=7.5% (same), but sometimes they write 25×3=215=7.5 and forget the % sign.
How to avoid:
Write each term with the % sign clearly:
25×3%=7.5%
Then sum carefully:
2%+6%+7.5%+8%=23.5%
So percentage error in X = 23.5%.
🔍 Mistake 4: Rounding off the final value incorrectly
The mistake:
Given X=2.763 and error =23.5%, students often round to 2 or 3 decimal places without considering the error magnitude.
Why it’s wrong:
The error determines the number of significant figures in the result.
Here, 23.5% of 2.763 is: …
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