Skip to content
NCERT Exemplar · Q38

Q.A physical quantity XX is related to four measurable quantities aa, bb, cc and dd as follows: X=a2b3c5/2d−2X = a^2 b^3 c^{5/2} d^{-2}. The percentage error in the measurement of aa, bb, cc and dd are 1%, 2%, 3% and 4%, respectively. What is the percentage error in quantity XX? If the value of XX calculated on the basis of the above relation is 2.763, to what value should you round off the result.

Rajasthan RbseLong· 3mImportance★★★★★est
91% · 60/66 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The percentage error in X=a2b3c5/2d−2X = a^2b^3c^{5/2}d^{-2} works out to 23.5%23.5\%; since this makes the absolute uncertainty on X=2.763X = 2.763 comparable to its ones digit, the value should be rounded to X≈3X \approx 3.

Percentage error in a power-law combination

For X=ambncpdqX = a^m b^n c^p d^q, errors combine as:

ΔXX×100=∣m∣(Δaa×100)+∣n∣(Δbb×100)+∣p∣(Δcc×100)+∣q∣(Δdd×100)\frac{\Delta X}{X}\times100 = |m|\left(\frac{\Delta a}{a}\times100\right) + |n|\left(\frac{\Delta b}{b}\times100\right) + |p|\left(\frac{\Delta c}{c}\times100\right) + |q|\left(\frac{\Delta d}{d}\times100\right)

Here X=a2b3c5/2d−2X = a^2b^3c^{5/2}d^{-2}, so m=2m=2, n=3n=3, p=5/2p=5/2, ∣q∣=2|q|=2, and the given percentage errors are 1%1\%, 2%2\%, 3%3\%, 4%4\% respectively.

Computing the total

ΔXX×100=2(1%)+3(2%)+52(3%)+2(4%)=2%+6%+7.5%+8%=23.5%\frac{\Delta X}{X}\times100 = 2(1\%) + 3(2\%) + \frac{5}{2}(3\%) + 2(4\%) = 2\% + 6\% + 7.5\% + 8\% = 23.5\%

Deciding how to round X = 2.763

The percentage error tells us the absolute uncertainty on the given value X=2.763X = 2.763:

ΔX=23.5100×2.763≈0.649\Delta X = \frac{23.5}{100} \times 2.763 \approx 0.649 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.