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Physics · Ch 5 — Work, Energy and Power

Kinetic Energy

5.4

Kinetic Energy

Kinetic Energy — The Energy of Motion

When a moving object collides with something, it can do work — it can push, deform, or break the target. A fast cricket ball shatters a window; a slow one barely dents it. This capacity to do work by virtue of motion is called kinetic energy. The word comes from the Greek kinētikos (moving).

The question is: how much work can a moving object do? To find out, we start from first principles — Newton's second law and the definition of work — and let the physics lead us to a precise formula.

Deriving the Expression for Kinetic Energy

Consider an object of mass mm initially at rest. A constant net force F\mathbf{F} acts on it, accelerating it uniformly along a straight line. After the force has acted through a displacement ss, the object reaches a speed vv.

The work done by the net force is:

W=FsW = F s

From Newton's second law, F=maF = ma, where aa is the constant acceleration. From kinematics (the equation v2=u2+2asv^2 = u^2 + 2as, with u=0u = 0):

v2=2as⇒s=v22av^2 = 2as \quad \Rightarrow \quad s = \frac{v^2}{2a}

Substituting both into the work expression:

W=(ma)(v22a)=12mv2W = (ma) \left( \frac{v^2}{2a} \right) = \frac{1}{2} m v^2

This quantity — the work required to bring the object from rest to speed vv — is defined as its kinetic energy KK:

K=12mv2K = \frac{1}{2} m v^2

K=12mv2K = \frac{1}{2} m v^2

The derivation assumed a constant force and straight-line motion, but the result is completely general. Kinetic energy depends only on mass and speed — not on the direction of motion, nor on the path taken to reach that speed.

Note

Kinetic energy is a scalar quantity. It has magnitude but no direction. A car moving north at 20 m/s has the same kinetic energy as the same car moving east at 20 m/s.

Properties of Kinetic Energy

The textbook lists three essential properties that follow directly from the definition K=12mv2K = \frac{1}{2} m v^2.

Property 1: Kinetic energy is always positive or zero.

Since mass m>0m > 0 and v2≥0v^2 \geq 0 for any real velocity, K≥0K \geq 0 always. The only way an object has zero kinetic energy is if it is at rest (v=0v = 0). There is no such thing as negative kinetic energy.

Property 2: Kinetic energy depends on the frame of reference.

Velocity is relative — its value changes depending on the observer's motion. Since KK depends on v2v^2, kinetic energy is also frame-dependent.

Watch out

A passenger sitting in a moving train has K=0K = 0 relative to the train, but non-zero kinetic energy relative to the ground. When solving problems, always specify the reference frame. The work-energy theorem (coming in the next section) holds in any inertial frame, but the numerical values of KK and work will differ between frames.

Property 3: Kinetic energy is a scalar, not a vector.

Unlike momentum (p=mv\mathbf{p} = m\mathbf{v}), which has direction, kinetic energy depends only on the square of the speed. Two objects with the same mass and speed but moving in opposite directions have the same kinetic energy. This makes energy calculations simpler in many situations — you never need to worry about signs from direction.

The Work-Kinetic Energy Relation (The Work-Energy Theorem)

The derivation above showed that the work done by the net force equals the change in kinetic energy. This is not a coincidence — it is a fundamental relation.

If an object's speed changes from viv_i to vfv_f under the action of a net force, the work done by that net force is:

W=12mvf2−12mvi2=Kf−Ki=ΔKW = \frac{1}{2} m v_f^2 - \frac{1}{2} m v_i^2 = K_f - K_i = \Delta K

Important

The work done by the net force (the resultant of all forces acting on the object) equals the change in kinetic energy. This is the work-energy theorem.

The proof for the general case (variable force, curved path) requires calculus, but the idea is the same: integrate F dsF \, ds along the path, and the result always equals 12mvf2−12mvi2\frac{1}{2} m v_f^2 - \frac{1}{2} m v_i^2.

Tip

The work-energy theorem is often the fastest way to find speed changes without dealing with acceleration or time. If you know the net work done on an object, you immediately know how its kinetic energy — and therefore its speed — has changed.

A Note on Units

From K=12mv2K = \frac{1}{2} m v^2, the SI unit of kinetic energy is:

kg⋅(m/s)2=kg⋅m2/s2\text{kg} \cdot (\text{m/s})^2 = \text{kg} \cdot \text{m}^2/\text{s}^2

This is the same as the unit of work: the joule (J). One joule is the kinetic energy of a 2 kg mass moving at 1 m/s (since 12×2×12=1\frac{1}{2} \times 2 \times 1^2 = 1 J). …