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Q.(i) Define order of reaction.

(ii) Explain the effect of concentration of reactant on rate constant.
(iii) The rate constants of a first order reaction at 500 K and 600 K are 0.03 s^-1 and 0.06 s^-1 respectively, then calculate the activation energy. [R = 8.314 JK^-1 mol^-1, log 2 = 0.3010] (1+1+2=4) OR
(i) Define molecularity of reaction.
(ii) Explain the effect of presence of catalyst on rate of reaction.
(iii) The initial concentration of reactant in a first order reaction was 1.0 x 10^-2 mol L^-1 at 300 K that was reduced to 0.5 x 10^-2 mol L^-1 after 30 minutes. Calculate the rate constant of the reaction at 300 K. [log 2 = 0.3010]
Rajasthan RbseRajasthan Board Senior Secondary Examination 2022Subjective· 4mImportance★★★★★
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Order of reaction is defined from the experimental rate law; the rate constant itself is independent of concentration (only rate depends on concentration); and using the two-temperature Arrhenius equation with the given rate constants at 500 K and 600 K gives an activation energy of about 17.29 kJ/mol.

  1. Order of a reaction: For a reaction whose experimentally determined rate law is Rate = k[A]^x[B]^y, the order of the reaction is defined as the sum of the powers (exponents) of the concentration terms in this rate law, i.e., order = x + y. It is an experimentally determined quantity (not necessarily equal to the stoichiometric coefficients) and can be zero, a positive integer, or even a fraction.
  2. Effect of concentration of reactant on the rate constant: The rate constant k is a proportionality constant in the rate law and is essentially INDEPENDENT of the concentration of the reactants - increasing the concentration of a reactant increases the RATE of the reaction (since rate = k[conc]^n), but it does NOT change the numerical value of k itself. The rate constant k depends only on the temperature of the reaction, the nature/identity of the reactants, and the presence of a catalyst - not on how much reactant is present. (This is why k is a useful, concentration-independent characteristic of a reaction at a given temperature.)
  3. Calculating the activation energy (Ea): Given: k1 = 0.03 s^-1 at T1 = 500 K; k2 = 0.06 s^-1 at T2 = 600 K; R = 8.314 J K^-1 mol^-1; log 2 = 0.3010 Using the Arrhenius two-point equation: …

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