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NCERT Exemplar · Q37

Q.Which of the following complexes are heteroleptic?

(i) [Cr(NH3)6]3+[Cr(NH_3)_6]^{3+}
(ii) [Fe(NH3)4Cl2]+[Fe(NH_3)_4Cl_2]^{+}
(iii) [Mn(CN)6]4−[Mn(CN)_6]^{4-}
(iv) [Co(NH3)4Cl2][Co(NH_3)_4Cl_2]
Rajasthan RbseMCQ· 1mImportance★★★★★
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A heteroleptic complex has two or more different types of ligands attached to the central metal ion. Among the given options, only (ii) [Fe(NH3)4Cl2]+[Fe(NH_3)_4Cl_2]^{+} and (iv) [Co(NH3)4Cl2][Co(NH_3)_4Cl_2] contain more than one kind of ligand, so they are heteroleptic.

Why this classification matters

In coordination chemistry, we classify complexes based on how many different kinds of ligands are bonded to the metal centre. This isn't just a naming exercise — it affects symmetry, isomerism, and often the chemical properties of the complex.

Homoleptic complexes: all ligands are identical.

Heteroleptic complexes: at least two different types of ligands are present.

The trick is to look past the numbers and focus on the identity of the ligands. A complex with six ammonia molecules is homoleptic; one with four ammonias and two chlorides is heteroleptic — even if the total number of ligands is the same.

Step-by-step analysis

  1. Option (i): [Cr(NH3)6]3+[Cr(NH_3)_6]^{3+}

    The only ligand present is ammonia (NH3NH_3). All six ligands are identical.

    → Homoleptic.

  2. Option (ii): [Fe(NH3)4Cl2]+[Fe(NH_3)_4Cl_2]^{+}

    Here we have two different ligands: ammonia (NH3NH_3) and chloride (Cl−Cl^-). Four of one kind, two of another — but the presence of even one different ligand makes it heteroleptic.

    → Heteroleptic.

  3. Option (iii): [Mn(CN)6]4−[Mn(CN)_6]^{4-}

    Only cyanide ions (CN−CN^-) are present. All six ligands are the same.

    → Homoleptic.

  4. Option (iv): [Co(NH3)4Cl2][Co(NH_3)_4Cl_2] …

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