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NCERT Exemplar · Q32

Q.[Note: two or more options may be correct] Which of the following binary mixtures will have same composition in liquid and vapour phase?

(i) Benzene - Toluene
(ii) Water-Nitric acid
(iii) Water-Ethanol
(iv) n-Hexane - n-Heptane
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A liquid–vapour mixture has identical composition in both phases only at an azeotropic point, where the system boils without change in composition. Among the options, water–nitric acid and water–ethanol form azeotropes.

When a liquid mixture boils, the vapour is usually richer in the more volatile component—that's the basis of distillation. But certain mixtures reach a special composition where the liquid and vapour have exactly the same makeup. At this point, called an azeotrope, the mixture behaves like a pure substance: it boils at a constant temperature and the vapour has the same mole fractions as the liquid. No amount of simple distillation can separate an azeotropic mixture further.

Azeotropes arise from strong intermolecular interactions between unlike molecules. When these interactions are significantly different from those in the pure components, Raoult's law breaks down and the vapour pressure curve develops an extremum (maximum or minimum). At that extremum, the composition of liquid and vapour coincide.

Now let's examine each pair:

  1. Benzene–Toluene (i)

    Both are non-polar aromatic hydrocarbons with very similar structures and intermolecular forces (London dispersion). They form an ideal solution that obeys Raoult's law closely across all compositions. The vapour is always enriched in benzene (the more volatile component), so liquid and vapour compositions differ at every point. No azeotrope forms.

  2. Water–Nitric acid (ii)

    This system exhibits strong hydrogen bonding and significant deviations from ideality. Water and nitric acid form a maximum-boiling azeotrope at approximately 68% (by mass) HNOX3\ce{HNO3} and 120.5 °C. At this composition, liquid and vapour have the same concentration.

  3. Water–Ethanol (iii)

    Ethanol and water hydrogen-bond with each other, but the ethanol–water interaction is weaker than water–water hydrogen bonds. This leads to positive deviation from Raoult's law and a minimum-boiling azeotrope at roughly 95.6% ethanol (by mass) and 78.2 °C. At the azeotropic point, both phases share the same composition—this is why you cannot distill absolute (100%) ethanol from a water–ethanol mixture by simple distillation. …

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