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Q.Define electric potential. Obtain an expression of electric potential due to an electric dipole at any point (r, theta). Draw necessary diagram. OR What is capacitor? Derive an expression of capacitance of the spherical capacitor. Draw necessary diagram.

Rajasthan RbseRajasthan Board Senior Secondary Examination 2020Subjective· 4mImportance★★★★★
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Figure — The answered alternative (potential due to a dipole at point (r,theta)) needs the dipole-potential geometry; t
Figure — The answered alternative (potential due to a dipole at point (r,theta)) needs the dipole-potential geometry; t

Electric potential is the work done per unit charge to bring a test charge from infinity to a point; for a dipole this potential falls off as 1/r21/r^2 and depends on the angle from the dipole axis.

Definition of electric potential:

The electric potential VV at a point in an electric field is defined as the amount of work done in bringing a unit positive test charge from infinity to that point, without any acceleration (i.e. quasi-statically, against the electric force):

V=Wq0V=\dfrac{W}{q_0}

Electric potential due to a dipole at point (r, θ):

Consider an electric dipole consisting of charges +q+q and −q-q separated by a distance 2a2a, with dipole moment p=q(2a)p=q(2a) directed from −q-q to +q+q. Let P be a point at distance rr from the centre O of the dipole, making angle θ\theta with the dipole axis.

Let r1r_1 = distance of P from +q+q, and r2r_2 = distance of P from −q-q.

The potential at P due to the two point charges (superposition):

V=14πε0(qr1−qr2)=q4πε0⋅r2−r1r1r2V=\dfrac{1}{4\pi\varepsilon_0}\left(\dfrac{q}{r_1}-\dfrac{q}{r_2}\right)=\dfrac{q}{4\pi\varepsilon_0}\cdot\dfrac{r_2-r_1}{r_1 r_2}

For a point far from the dipole (r≫ar\gg a, the "short dipole" approximation), using the geometry (dropping perpendiculars from ±q onto the line OP):

r1≈r−acos⁡θ,r2≈r+acos⁡θr_1\approx r-a\cos\theta, \qquad r_2\approx r+a\cos\theta

So: r2−r1≈2acos⁡θr_2-r_1\approx 2a\cos\theta, and r1r2≈r2r_1 r_2\approx r^2.

Substituting:

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