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Physics · Ch 13 — Nuclei

Radioactivity

13.6

Radioactivity

Radioactivity: A Nuclear Phenomenon

Radioactivity was discovered in 1896 by Henri Becquerel, quite by accident. While studying how certain compounds glow after being exposed to visible light, Becquerel placed some uranium-potassium sulphate on a photographic plate wrapped in black paper, separated by a silver sheet. When he developed the plate hours later, it was blackened — something had passed through both the paper and the silver. That "something" was radiation from the uranium compound.

Further experiments revealed that radioactivity is a nuclear phenomenon: an unstable nucleus spontaneously decays, emitting particles or energy. This process is called radioactive decay. Three types occur in nature:

  1. α\alpha-decay — the nucleus emits a helium nucleus, 24He{}_{2}^{4}\text{He}.
  2. β\beta-decay — the nucleus emits an electron (β−\beta^-) or a positron (β+\beta^+). A positron has the same mass as an electron but opposite charge.
  3. γ\gamma-decay — the nucleus emits high-energy photons (hundreds of keV or more).
Note

The term "radioactivity" was coined by Marie Curie. The radiation itself is invisible to the naked eye — its effects are detected through photographic plates, Geiger counters, or scintillation detectors.


The Three Decay Modes in Detail

α\alpha-Decay

In α\alpha-decay, the parent nucleus loses two protons and two neutrons — exactly the composition of a helium-4 nucleus. The general equation is:

ZAX  ⟶  Z−2A−4Y  +  24He{}_{Z}^{A}\text{X} \;\longrightarrow\; {}_{Z-2}^{A-4}\text{Y} \;+\; {}_{2}^{4}\text{He}

The emitted α\alpha-particle carries a positive charge and is relatively heavy. Because it interacts strongly with matter, it has a short range in air (a few centimetres) and can be stopped by a sheet of paper.

Important

The daughter nucleus Y has atomic number Z−2Z-2 and mass number A−4A-4. It is a different element from X.

β\beta-Decay

In β\beta-decay, a neutron inside the nucleus transforms into a proton (or vice versa), and an electron or positron is emitted. There are two types:

  • β−\beta^- decay: A neutron converts into a proton, an electron, and an antineutrino (νˉe\bar{\nu}_e). The electron is emitted.

ZAX  ⟶  Z+1AY  +  e−  +  νˉe{}_{Z}^{A}\text{X} \;\longrightarrow\; {}_{Z+1}^{A}\text{Y} \;+\; e^- \;+\; \bar{\nu}_e

  • β+\beta^+ decay: A proton converts into a neutron, a positron, and a neutrino (νe\nu_e). The positron is emitted.

ZAX  ⟶  Z−1AY  +  e+  +  νe{}_{Z}^{A}\text{X} \;\longrightarrow\; {}_{Z-1}^{A}\text{Y} \;+\; e^+ \;+\; \nu_e

The neutrino and antineutrino are nearly massless, neutral particles that interact very weakly with matter. They were first postulated by Wolfgang Pauli to conserve energy and momentum in β\beta-decay, and were later detected experimentally.

Watch out

In β\beta-decay, the mass number AA does not change — only the atomic number ZZ changes by ±1\pm 1. The daughter nucleus is an isobar of the parent.

γ\gamma-Decay

γ\gamma-decay occurs when a nucleus in an excited state (often left after α\alpha or β\beta decay) drops to a lower energy state by emitting a high-energy photon. The nucleus itself does not change its composition:

ZAX∗  ⟶  ZAX  +  γ{}_{Z}^{A}\text{X}^* \;\longrightarrow\; {}_{Z}^{A}\text{X} \;+\; \gamma

The asterisk denotes an excited nuclear state. γ\gamma-rays are electromagnetic radiation with wavelengths shorter than X-rays and are extremely penetrating — they can pass through several centimetres of lead.

Note

γ\gamma-decay is analogous to the emission of visible light by excited atoms, but the energy involved is millions of times larger (keV to MeV, compared to a few eV for atomic transitions).


Key Properties of Radioactive Decay

The textbook lists several fundamental properties of radioactive decay. Each is stated and proved below.

Property 1: Radioactive decay is a statistical process

You cannot predict exactly when a given unstable nucleus will decay. However, for a large sample of identical nuclei, the decay follows a well-defined statistical law. This is the law of radioactive decay.

›Proof

Consider a sample containing N(t)N(t) identical radioactive nuclei at time tt. The number of decays dNdN occurring in a short time interval dtdt is proportional to N(t)N(t) and to dtdt:

dN=−λN(t) dtdN = -\lambda N(t)\, dt

where λ\lambda is the decay constant (a positive constant characteristic of the isotope). The negative sign indicates that NN decreases with time.

Rearranging:

dNN=−λ dt\frac{dN}{N} = -\lambda\, dt

Integrate both sides:

∫N0N(t)dNN=−λ∫0tdt\int_{N_0}^{N(t)} \frac{dN}{N} = -\lambda \int_0^t dt

ln⁡N(t)−ln⁡N0=−λt\ln N(t) - \ln N_0 = -\lambda t

ln⁡N(t)N0=−λt\ln \frac{N(t)}{N_0} = -\lambda t

Exponentiating:

N(t)=N0e−λtN(t) = N_0 e^{-\lambda t}

This is the exponential decay law. N0N_0 is the number of nuclei at t=0t=0.

Property 2: The decay constant λ\lambda is related to the half-life T1/2T_{1/2}

The half-life is the time required for half of the original nuclei to decay. Set N(T1/2)=N0/2N(T_{1/2}) = N_0/2:

N02=N0e−λT1/2\frac{N_0}{2} = N_0 e^{-\lambda T_{1/2}}

12=e−λT1/2\frac{1}{2} = e^{-\lambda T_{1/2}}

Take natural logarithms:

ln⁡(12)=−λT1/2\ln\left(\frac{1}{2}\right) = -\lambda T_{1/2}

−ln⁡2=−λT1/2-\ln 2 = -\lambda T_{1/2}

T1/2=ln⁡2λ≈0.693λT_{1/2} = \frac{\ln 2}{\lambda} \approx \frac{0.693}{\lambda}

T1/2=ln⁡2λT_{1/2} = \frac{\ln 2}{\lambda}

Property 3: The mean life τ\tau is the average lifetime of a nucleus

The mean life (or average life) τ\tau is the reciprocal of the decay constant:

τ=1λ\tau = \frac{1}{\lambda}

›Proof

The number of nuclei that decay between tt and t+dtt+dt is ∣dN∣=λN0e−λtdt|dN| = \lambda N_0 e^{-\lambda t} dt. Each of these lived for time tt. The total "lifetime" of all nuclei is:

∫0∞t ∣dN∣=∫0∞tλN0e−λtdt\int_0^\infty t\,|dN| = \int_0^\infty t \lambda N_0 e^{-\lambda t} dt

The average lifetime is this total divided by N0N_0:

τ=1N0∫0∞tλN0e−λtdt=λ∫0∞te−λtdt\tau = \frac{1}{N_0} \int_0^\infty t \lambda N_0 e^{-\lambda t} dt = \lambda \int_0^\infty t e^{-\lambda t} dt

Using the standard integral ∫0∞te−atdt=1/a2\int_0^\infty t e^{-at} dt = 1/a^2:

τ=λ⋅1λ2=1λ\tau = \lambda \cdot \frac{1}{\lambda^2} = \frac{1}{\lambda}

The relationship between half-life and mean life is:

T1/2=τln⁡2≈0.693 τT_{1/2} = \tau \ln 2 \approx 0.693\,\tau

Property 4: Activity RR is the rate of decay …