Q.Find the rate of change of the area of a circle with respect to its radius r when r=5 cm.
Sikkim CbseNCERTSubjective· 2mImportance★★★★★est
85% · 17/20 Questions
✓ Free question
Concept understanding — Instantaneous Rate of Change and Derivative
Instantaneous Rate of Change and Derivative
Imagine you're driving a car. Your speedometer doesn't tell you your average speed over the last hour — it tells you your speed right now, at this exact instant. That's the core idea: the instantaneous rate of change is how fast something is changing at a single moment.
From Average to Instantaneous
You already know average rate of change. If you drive 120 km in 2 hours, your average speed is 60 km/h. But you didn't do 60 the whole time — you stopped at lights, sped up on the highway, slowed for a turn. The average hides all that.
The formula for average rate of change of a function f(x) from x=a to x=b is:
b−af(b)−f(a)
That's just the slope of the line connecting the two points (a,f(a)) and (b,f(b)).
Now, to get the rate atx=a, you'd want the second point to be as close as possible to the first. Let the second point be x=a+h, where h is a tiny step. The average rate over that tiny interval is:
hf(a+h)−f(a)
If you make h smaller and smaller — approaching zero — the average rate over that shrinking interval gets closer and closer to the rate at the instant x=a. That limit is the instantaneous rate of change.
The Precise Definition
The derivative of f at x=a, denoted f′(a) or dxdfx=a, is defined as:
f′(a)=limh→0hf(a+h)−f(a)
provided this limit exists.
Important
The derivative is the limit of the average rate of change as the interval shrinks to zero. It is the slope of the tangent line to the curve at that point.
What It Means Geometrically
Picture the graph of f(x). The average rate from a to a+h is the slope of the secant line through (a,f(a)) and (a+h,f(a+h)). As h→0, that secant line pivots and approaches the tangent line — the line that just touches the curve at that single point. The slope of that tangent line is f′(a).
So the derivative answers two questions at once:
How fast is f changing at x=a? (rate interpretation)
What is the slope of the curve at x=a? (geometric interpretation)
A Simple Example
Take f(x)=x2. Find the instantaneous rate of change at x=3.
So at x=3, the function x2 is increasing at a rate of 6 units per unit change in x. The tangent line at (3,9) has slope 6.
Tip
For a polynomial, you can often skip the limit by using the power rule: derivative of xn is nxn−1. For x2, that gives 2x, so at x=3 it's 6. But always remember: the power rule comes from the limit definition — it's a shortcut, not a replacement for understanding.
Why This Matters
The derivative is the foundation of calculus because it lets you study change at an instant — velocity, acceleration, growth rates, marginal cost, slope of a curve at a point. Every optimization problem (find the maximum profit, the minimum distance) and every differential equation (how populations grow, how circuits behave) starts here.
The key takeaway: the derivative is a limit of averages. It's not magic — it's just taking the average over an interval so small that the interval itself becomes negligible.
The rate of change of area with respect to radius is found by differentiating A=πr2 using the power rule, then evaluating the derivative at the given radius.
✓Final answer
drdAr=5=10π≈31.42cm2/cm
Differentiate the area of a circle with respect to its radius and evaluate at r=5 cm.
Area of a circle of radius r:
A=πr2
with power rule drd(rn)=nrn−1.
Write the area formula.
A=πr2
Differentiate A with respect to r.
drdA=π⋅2r=2πr
Substitute the given value r=5 cm.
drdAr=5=2π(5)=10π
Numeric value. Using π≈3.1416:
10π≈10×3.1416=31.416cm2/cm
Self-check. Dimensionally, A is in cm2 and r in cm, so drdA has units cm2/cm = cm, consistent with a rate of area-change per unit radius. Also, drdA=2πr is exactly the circumference of the circle at that radius — a well-known geometric check (a thin outer ring of width dr has area ≈2πrdr).