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Worked Examples · Example 14

Q.Find the centre and radius of the circle x2+y2−8x+10y−12=0x^2 + y^2 - 8x + 10y - 12 = 0.

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Compare the given equation with the general circle form to read off centre and radius.

For x2+y2+2gx+2fy+c=0x^2+y^2+2gx+2fy+c=0: centre =(−g,−f)=(-g,-f), radius =g2+f2−c=\sqrt{g^2+f^2-c}.

  1. Given: x2+y2−8x+10y−12=0x^2+y^2-8x+10y-12=0. Compare with x2+y2+2gx+2fy+c=0x^2+y^2+2gx+2fy+c=0.
  2. Match coefficients: 2g=−8⇒g=−42g=-8\Rightarrow g=-4; 2f=10⇒f=52f=10\Rightarrow f=5; c=−12c=-12.
  3. Centre =(−g,−f)=(−(−4),−5)=(4,−5)=(-g,-f)=(-(-4),-5)=(4,-5).
  4. Radius =g2+f2−c=(−4)2+52−(−12)=16+25+12=53=\sqrt{g^2+f^2-c}=\sqrt{(-4)^2+5^2-(-12)}=\sqrt{16+25+12}=\sqrt{53}. …

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