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Worked Examples · Example 15

Q.If a parabolic reflector is 20 cm in diameter and 5 cm deep, find the focus.

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✓ Free question

Model the reflector's cross-section as a parabola y2=4axy^2=4ax; use the given diameter and depth as a point on the curve to find aa (the focal distance).

Parabola with vertex at origin, axis along the x-axis, opening right: y2=4axy^2=4ax, where the focus is at (a,0)(a,0), i.e. a distance aa from the vertex.

  1. Place the vertex of the parabolic reflector at the origin, with its axis along the x-axis (direction of depth).
  2. The reflector is 20 cm in diameter, so at the rim the half-width is y=202=10y=\dfrac{20}{2}=10 cm; the depth there is x=5x=5 cm.
  3. Substitute the point (5,10)(5,10) into y2=4axy^2=4ax:

102=4a(5)⇒100=20a10^2=4a(5)\Rightarrow100=20a

  1. Solve: a=10020=5a=\dfrac{100}{20}=5.
  2. Self-check: with a=5a=5, at x=5x=5: y2=4(5)(5)=100⇒y=10y^2=4(5)(5)=100\Rightarrow y=10 ✓, matching the given radius of the mouth (10 cm, i.e. 20 cm diameter).
✓Final answer

The focus lies on the axis at a distance a=5a=5 cm from the vertex.

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