Q.If a parabolic reflector is 20 cm in diameter and 5 cm deep, find the focus.
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Concept understanding — Length of the Latus Rectum
What is the Latus Rectum? A First Look
Imagine you draw a parabola, ellipse, or hyperbola — a conic section. Each of these curves has a special line segment that cuts straight across it, passing through the focus and running parallel to the directrix. That segment is the latus rectum.
The name comes from Latin: latus means "side" and rectum means "straight." So it's literally the "straight side" of the curve. For a student meeting it for the first time, think of it as the width of the curve at the focus — how wide the opening is right at that special point.
Intuition First
Take a parabola that opens upward, like y2=4ax. Its focus is at (a,0). If you draw a vertical line through that focus, it will hit the parabola at two points — one above, one below. The distance between those two intersection points is the length of the latus rectum.
Why does this matter? Because it tells you how "fat" or "skinny" the curve is. A larger latus rectum means a wider opening; a smaller one means a tighter, narrower curve. For ellipses and hyperbolas, it also relates directly to the shape's eccentricity.
The Precise Statement
For a conic section with focus at (a,0) and directrix x=−a (standard parabola y2=4ax):
Length of latus rectum=4a
But that's just the parabola. Here are the exact formulas for all three conics:
Conic
Standard Equation
Length of Latus Rectum
Parabola
y2=4ax
4a
Ellipse
a2x2+b2y2=1 (a > b)
a2b2
Hyperbola
a2x2−b2y2=1
a2b2
Notice something interesting: the ellipse and hyperbola share the same formula. That's because both have two foci and the latus rectum is defined through either focus.
Why That Formula? A Quick Derivation
For the parabola y2=4ax, the focus is at (a,0). A line through the focus parallel to the directrix is vertical (since the directrix is vertical x=−a). So the line is x=a.
Substitute x=a into y2=4ax:
y2=4a(a)=4a2
y=±2a
The two intersection points are (a,2a) and (a,−2a). The distance between them is 4a. That's it.
Tip
For any conic, the latus rectum is always found by substituting the focus's x-coordinate into the equation and solving for y. The distance between the two y-values is the length.
Common Mistake to Avoid
Watch out
Do not confuse the latus rectum with the focal width — they are the same thing. But some students mistakenly think the latus rectum is the distance from the focus to the curve. It is not. It is the full chord through the focus, perpendicular to the axis.
Also, for ellipses and hyperbolas, there are two latera recta — one through each focus. They have the same length.
Why It Matters in Exams
You will be asked to:
Find the length of the latus rectum given the equation of a conic.
Use it to find a or b when the length is given.
Relate it to eccentricity (especially for ellipses: e=1−a2b2, so the latus rectum a2b2 ties directly to e).
Important
For a parabola, the latus rectum is 4a. For an ellipse or hyperbola, it is a2b2. Memorize these — they appear in nearly every conic section problem.
One Final Intuition
Picture a parabola like a U-shaped slide. The latus rectum is the width of that slide exactly at the level of the focus. For an ellipse, imagine an oval — the latus rectum is the length of the vertical line segment that passes through one focus and touches the ellipse at two points. It's a concrete, measurable property that captures how "stretched" or "squashed" the curve is at its focal point.
Modelling the reflector's cross-section as a parabola y2=4ax opening from the vertex, the given diameter and depth give a point on the curve that fixes the focal distance a.
✓Final answer
The focus is 5 cm from the vertex.
Model the reflector's cross-section as a parabola y2=4ax; use the given diameter and depth as a point on the curve to find a (the focal distance).
Parabola with vertex at origin, axis along the x-axis, opening right: y2=4ax, where the focus is at (a,0), i.e. a distance a from the vertex.
Place the vertex of the parabolic reflector at the origin, with its axis along the x-axis (direction of depth).
The reflector is 20 cm in diameter, so at the rim the half-width is y=220=10 cm; the depth there is x=5 cm.
Substitute the point (5,10) into y2=4ax:
102=4a(5)⇒100=20a
Solve: a=20100=5.
Self-check: with a=5, at x=5: y2=4(5)(5)=100⇒y=10✓, matching the given radius of the mouth (10 cm, i.e. 20 cm diameter).
✓Final answer
The focus lies on the axis at a distance a=5 cm from the vertex.