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Worked Examples · Example 41
Q.

In the early years of the telecom sector, PCOs (Public Call Offices) became ubiquitous in India. However, spread of mobile services declined its number in subsequent years. Telecom Statistics India report (2018) gives following figures of PCOs in recent years:

Year2009201020112012201320142015201620172018
No of PCOs (in Lakh)6245.9033.3020.1012.609.577.375.894.523.60

Source: Telecom Statistics India report (2018) (TRAI records), https://dot.gov.in/sites/default/files/statistical%20Bulletin-2018.pdf

Plot the given data and comment on the direction/type of skewness of the distribution.

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The number of PCOs fell from 6262 lakh (2009) to 3.603.60 lakh (2018); mean (20.4920.49 lakh) exceeds the median (11.0911.09 lakh), so the distribution of yearly PCO counts is positively skewed, matching the steeply-falling, right-tailed shape of the plotted curve.

Graph: plot Year (x-axis) against "No. of PCOs (in lakh)" (y-axis) as a line/bar chart.

Skewness rule of thumb: if Mean >> Median, the distribution is positively (right-) skewed; if Mean << Median, it is negatively (left-) skewed; if Mean == Median, it is symmetric.

  1. Data:
Year2009201020112012201320142015201620172018
PCOs (lakh)6245.9033.3020.1012.609.577.375.894.523.60
  1. Plot: with Year on the x-axis and "No. of PCOs (in lakh)" on the y-axis, the plotted curve starts very high in 2009, falls sharply through 2010-2013, and then flattens out close to the axis from 2015 to 2018 — a steeply decaying, "reverse-J" shaped curve.
  2. n=10n=10; ∑xi=62+45.90+33.30+20.10+12.60+9.57+7.37+5.89+4.52+3.60=204.85\sum x_i=62+45.90+33.30+20.10+12.60+9.57+7.37+5.89+4.52+3.60=204.85.
  3. Mean =204.8510=20.485=\dfrac{204.85}{10}=20.485 lakh.
  4. Sort ascending: 3.60,4.52,5.89,7.37,9.57,12.60,20.10,33.30,45.90,623.60,4.52,5.89,7.37,9.57,12.60,20.10,33.30,45.90,62. With n=10n=10 (even), median =5th+6th2=9.57+12.602=11.085=\dfrac{5^{th}+6^{th}}{2}=\dfrac{9.57+12.60}{2}=11.085 lakh. …

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