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Exercise 7.4 · Q1

Q.In a certain language, if CAMEL is coded as DBNFM then how will ROOM be coded?

a) NPPQ
b) SPPN
c) PPON
d) NQQP
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The code shifts every letter one step forward in the alphabet (+1+1); applying the same +1+1 shift to R-O-O-M gives S-P-P-N.

Letter-shift coding rule: if each letter of a word is replaced by the letter that is nn positions ahead of it in the alphabet, the code of any new word is found by shifting EVERY one of its letters by the same nn.

Alphabet positions: A=1,B=2,…,Z=26A=1, B=2, \dots, Z=26.

  1. Write CAMEL and DBNFM letter by letter with their alphabet positions: C(3)→D(4)C(3)\to D(4), A(1)→B(2)A(1)\to B(2), M(13)→N(14)M(13)\to N(14), E(5)→F(6)E(5)\to F(6), L(12)→M(13)L(12)\to M(13).
  2. Each position increases by exactly 11: 3→4, 1→2, 13→14, 5→6, 12→133\to4,\ 1\to2,\ 13\to14,\ 5\to6,\ 12\to13. So the rule is "shift every letter +1+1".
  3. Apply the same +1+1 shift to R-O-O-M: R(18)→S(19)R(18)\to S(19); O(15)→P(16)O(15)\to P(16); O(15)→P(16)O(15)\to P(16); M(13)→N(14)M(13)\to N(14).
  4. Reading the shifted letters in order gives S,P,P,NS,P,P,N → SPPN.
  5. Self-check: reversing the shift on SPPN (−1-1 each letter) gives S→R, P→O, P→O, N→MS\to R,\ P\to O,\ P\to O,\ N\to M = ROOM. ✓
✓Final answer

(b) SPPN

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