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Miscellaneous Examples · Example 52

Q.How many words, with or without meaning, each of 2 vowels and 3 consonants can be formed from the letters of the word DAUGHTER?

Sikkim CbseNCERTSubjective· 3mImportance★★★★★est
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✓ Free question

DAUGHTER has 8 distinct letters (3 vowels, 5 consonants); pick 2 vowels and 3 consonants by combinations, then permute the 5 selected letters to form each word.

To choose then arrange: first select the required letters using nCr{}^nC_r for each letter-type, then arrange the total selected letters (all distinct here) in k!k! ways, where kk = total letters in the word.

  1. DAUGHTER == D, A, U, G, H, T, E, R — 8 distinct letters.
  2. Vowels present: A, U, E — a total of 3 vowels.
  3. Consonants present: D, G, H, T, R — a total of 5 consonants.
  4. Choose 2 vowels out of 3: 3C2=3{}^3C_2=3.
  5. Choose 3 consonants out of 5: 5C3=5×4×33×2×1=10{}^5C_3=\dfrac{5\times4\times3}{3\times2\times1}=10.
  6. Each selection gives 2+3=52+3=5 distinct letters, which can be arranged (permuted) in 5!5! ways to form a word: 5!=1205!=120.
  7. Total words =3C2×5C3×5!=3×10×120=3,600={}^3C_2\times{}^5C_3\times5! = 3\times10\times120=3{,}600.
✓Final answer

Number of words =3C2×5C3×5!=3×10×120=3,600= {}^3C_2\times{}^5C_3\times5! = 3\times10\times120 = 3{,}600

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