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Exercises · 18.7

Q.Explain the role of Na+ in the generation of action potential.

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When a neuron is stimulated its membrane briefly becomes freely permeable to sodium ions; the resulting inrush of Na+ reverses the membrane's polarity, and this depolarisation is the action potential — the nerve impulse.

To see the role of sodium, it helps to first recall the resting neuron. A neuron at rest is an excitable cell whose membrane is kept polarised. The membrane is selectively permeable: it is comparatively permeable to potassium ions (K+) but almost impermeable to sodium ions (Na+), and impermeable to the large negatively charged proteins inside. As a result the axoplasm holds a high concentration of potassium and a low concentration of sodium, while the fluid outside holds a high concentration of sodium and a low concentration of potassium. A sodium-potassium pump keeps these gradients up by moving three sodium ions out for every two potassium ions it brings in. Because of this arrangement the outer surface of the resting membrane is positively charged and the inner surface negatively charged — the membrane is polarised, and this charge difference is the resting potential.

Sodium's role begins the instant a stimulus is applied. When a stimulus reaches a point on the polarised membrane, the membrane there suddenly becomes freely permeable to sodium ions. Driven by both its concentration gradient and the electrical attraction, sodium rushes inward in a rapid influx.

This inflow of positive charge has a dramatic effect. It reverses the polarity at that site: the outer surface, formerly positive, now becomes negative, and the inner surface, formerly negative, now becomes positive. The membrane at that point is said to be depolarised, and the electrical potential difference produced across it is called the action potential — which is precisely what we mean by a nerve impulse. …

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