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Miscellaneous Exercise · Q12

Q.Find the derivative of (ax+b)n(ax + b)^n.

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Apply the chain rule: differentiate the outer power, keep the inner function, then multiply by the derivative of the inner linear term. The result is na(ax+b)n−1\boxed{n a (ax + b)^{n-1}}.

Why the chain rule?

The function (ax+b)n(ax + b)^n is a composition: an outer function unu^n wrapped around an inner function u=ax+bu = ax + b. Whenever you have one function nested inside another, the chain rule tells you how the rate of change propagates through the layers. The derivative of the outer function (with respect to its input) gets multiplied by the derivative of the inner function (with respect to xx).

Think of it this way: if uu changes at rate aa with respect to xx, and unu^n changes at rate nun−1n u^{n-1} with respect to uu, then the overall rate of change with respect to xx is the product of these two rates.

Step-by-step derivation

  1. Identify the structure.

    Let u=ax+bu = ax + b. Then our function becomes f(x)=unf(x) = u^n.

  2. Differentiate the outer function.

    The power rule gives us ddu(un)=nun−1\frac{d}{du}(u^n) = n u^{n-1}.

  3. Differentiate the inner function.

    The linear term u=ax+bu = ax + b has derivative dudx=a\frac{du}{dx} = a.

  4. Apply the chain rule.

    Multiply the derivative of the outer function (evaluated at the inner function) by the derivative of the inner function:

ddx(ax+b)n=n(ax+b)n−1⋅a\frac{d}{dx}(ax + b)^n = n(ax + b)^{n-1} \cdot a

  1. Simplify. Rearrange to put the constant factor first: …

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