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NCERT Exemplar · Q26

Q.Fill in the blank: If −34x≤−3\dfrac{-3}{4}x \le -3, then xx ___ 44.

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Dividing both sides of an inequality by a negative number reverses the inequality sign; here x≥4x \ge 4.

When you multiply or divide both sides of an inequality by a negative number, the inequality flips direction. This is the heart of the problem. Think of it on a number line: if a<ba < b, then −a>−b-a > -b because negation reflects numbers across zero, reversing their order.

We have −34x≤−3\dfrac{-3}{4}x \le -3 and need to isolate xx.

Step-by-step solution:

  1. Identify what operation isolates xx.

    The variable xx is multiplied by −34\dfrac{-3}{4}. To isolate it, multiply both sides by the reciprocal of −34\dfrac{-3}{4}, which is 4−3=−43\dfrac{4}{-3} = -\dfrac{4}{3}.

  2. Recognize that the reciprocal is negative.

    Since −43-\dfrac{4}{3} is negative, multiplying both sides by it will reverse the inequality sign. The ≤\le becomes ≥\ge.

  3. Perform the multiplication.

−34x⋅(−43)≥−3⋅(−43)\dfrac{-3}{4}x \cdot \left(-\dfrac{4}{3}\right) \ge -3 \cdot \left(-\dfrac{4}{3}\right)

On the left side: …

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