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Worked Examples · Example 8

Q.An arrow diagram relates two sets. Set P={9,4,25}P = \{9, 4, 25\} and set Q={5,3,2,1,−2,−3,−5}Q = \{5, 3, 2, 1, -2, -3, -5\}. Arrows are drawn from PP to QQ as follows: 99 is joined to both 33 and −3-3; 44 is joined to both 22 and −2-2; and 2525 is joined to both 55 and −5-5 (the element 11 of QQ receives no arrow). Write this relation

(i) in set-builder form,
(ii) in roster form. What is its domain and range?
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The arrows join each element of PP to both of its square roots in QQ: 9→±39\to\pm 3, 4→±24\to\pm 2, 25→±525\to\pm 5. The common rule is “xx is the square of yy”, i.e. x=y2x = y^2, giving R={(9,3),(9,−3),(4,2),(4,−2),(25,5),(25,−5)}R = \{(9,3),(9,-3),(4,2),(4,-2),(25,5),(25,-5)\} with domain {4,9,25}\{4,9,25\} and range {−5,−3,−2,2,3,5}\{-5,-3,-2,2,3,5\}.

Concept

A relation from PP to QQ is a subset of P×QP \times Q. To read it off an arrow diagram, list every ordered pair (x,y)(x,y) for which an arrow runs from x∈Px \in P to y∈Qy \in Q, then look for a single algebraic rule the pairs share.

Reading the arrows

P={9,4,25}P = \{9, 4, 25\} and Q={5,3,2,1,−2,−3,−5}Q = \{5, 3, 2, 1, -2, -3, -5\}. The arrows give

9→3,  9→−3,4→2,  4→−2,25→5,  25→−5.9 \to 3,\ \ 9 \to -3,\qquad 4 \to 2,\ \ 4 \to -2,\qquad 25 \to 5,\ \ 25 \to -5.

Finding the rule

Check each pair:

32=9, (−3)2=9,22=4, (−2)2=4,52=25, (−5)2=25.3^2 = 9,\ (-3)^2 = 9,\qquad 2^2 = 4,\ (-2)^2 = 4,\qquad 5^2 = 25,\ (-5)^2 = 25.

In every pair the first coordinate is the square of the second, so x=y2x = y^2 (“xx is the square of yy”). Note the element 1∈Q1 \in Q has no square in PP (since 12=1∉P1^2 = 1 \notin P), so it is not related to anything — consistent with it receiving no arrow.

(i) Set-builder form …

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