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Miscellaneous Exercise · Q17

Q.A manufacturer reckons that the value of a machine, which costs him Rs 15625, will depreciate each year by 20%. Find the estimated value at the end of 5 years.

Sikkim CbseNCERTSubjective· 3mImportance★★★★★
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The machine’s value falls by a fixed percentage each year, so we use the depreciation formula V=P(1−r100)nV = P \left(1 - \frac{r}{100}\right)^n. With P=15625P = 15625, r=20r = 20, and n=5n = 5, the value after 5 years is Rs 5120.


Why the Depreciation Formula Works

When an asset loses value by a constant percentage each year, the decrease is not a fixed amount — it’s proportional to the current value. That means the value at the end of each year is the previous year’s value multiplied by (1−r100)(1 - \frac{r}{100}), where rr is the depreciation rate. This is exactly like compound interest, but with a negative rate. So after nn years, the formula is:

V=P(1−r100)nV = P \left(1 - \frac{r}{100}\right)^n

Here, PP is the initial cost, rr is the annual depreciation percentage, and nn is the number of years.


Step-by-Step Solution

  1. Identify the given values.

    The machine costs Rs 15625 initially, so P=15625P = 15625.

    It depreciates by 20% each year, so r=20r = 20.

    We need the value after 5 years, so n=5n = 5.

  2. Write the depreciation factor.

    Each year, the machine retains 100%−20%=80%100\% - 20\% = 80\% of its value.

    As a decimal, that’s 0.800.80, or as a fraction, 80100=45\frac{80}{100} = \frac{4}{5}.

    So the factor is (1−20100)=45\left(1 - \frac{20}{100}\right) = \frac{4}{5}.

  3. Apply the formula.

V=15625×(45)5V = 15625 \times \left(\frac{4}{5}\right)^5

  1. Compute (45)5\left(\frac{4}{5}\right)^5. (45)5=4555=10243125\left(\frac{4}{5}\right)^5 = \frac{4^5}{5^5} = \frac{1024}{3125} …

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