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Exercise 13.2 · Q8
Q.

Find the mean and variance for the following frequency distribution.

ClassesFrequencies
0-105
10-208
20-3015
30-4016
40-506
Sikkim CbseNCERTSubjective· 5mImportance★★★★★est
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Using class midpoints, the mean is 27 and the variance is 132.

Because the data is grouped, each class is represented by its midpoint xix_i. The mean is the frequency-weighted average of the midpoints, and the variance is the frequency-weighted average of the squared deviations from that mean.

Step 1 — Midpoints, total frequency, and ∑fixi\sum f_i x_i.

Midpoints: 5, 15, 25, 35, 45.

Classfif_ixix_ifixif_i x_i
0–105525
10–20815120
20–301525375
30–401635560
40–50645270
Total501350

Step 2 — Mean.

xˉ=∑fixiN=135050=27.\bar{x}=\frac{\sum f_i x_i}{N}=\frac{1350}{50}=27.

Step 3 — Squared deviations from the mean, weighted by frequency.

| xix_i | fif_i | xi−27x_i-27 | (xi−27)2(x_i-27)^2 | fi(xi−27)2f_i(x_i-27)^2 | …

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