NCERT Exemplar · Q27
Q.A tuning fork vibrating at 512 Hz is held just above the open upper end of a long vertical glass tube. The lower end of the tube is joined by a flexible rubber pipe to a movable water reservoir, so that raising or lowering the reservoir changes the height of the water inside the tube and hence the length of the air column above the water. The water level is gradually lowered from near the top, and the first position of maximum sound intensity (loudest resonance) is heard when the water surface is 17 cm below the open end. The room temperature is C. Calculate
(a) the speed of sound in air at room temperature,
(b) the speed of sound in air at C, and
(c) whether there would be any difference in the observations if the water in the tube were replaced by mercury.
Sikkim CbseShort· 3mImportance★★★★★est
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Start your 14-day free trial to unlock the full solution →The water surface closes the bottom of the air column, so the first loud resonance occurs when the column length equals a quarter-wavelength. That gives m/s at C; scaling by gives m/s at C. Replacing water with mercury does not change the air-column length, so the observation is essentially unchanged.
(a) Speed of sound at room temperature
The tube acts as a pipe closed at the water surface. Its first (fundamental) resonance occurs when the air-column length is a quarter of a wavelength (neglecting the small end correction):
(b) Speed of sound at C
For a gas the speed of sound obeys with in kelvin (C K, C K):
(c) Water replaced by mercury …
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