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Exercises · 14.8

Q.A transverse harmonic wave on a string is described by
[!FORMULA] y(x,t)=3.0sin⁡(36 t+0.018 x+π/4)y(x, t) = 3.0 \sin(36\,t + 0.018\,x + \pi/4)
where xx and yy are in cm and tt in s. The positive direction of xx is from left to right.

(a) Is this a travelling wave or a stationary wave? If it is travelling, what are the speed and direction of its propagation?
(b) What are its amplitude and frequency?
(c) What is the initial phase at the origin?
(d) What is the least distance between two successive crests in the wave?
Sikkim CbseNCERTSubjective· 3mImportance★★★★★est
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It is a travelling wave moving in the negative xx-direction (right to left) with speed v=20 m/sv = 20\ \text{m/s}. Amplitude A=3.0 cmA = 3.0\ \text{cm}, frequency f=18/π≈5.73 Hzf = 18/\pi \approx 5.73\ \text{Hz}, initial phase at the origin π/4\pi/4, and the least distance between successive crests (wavelength) λ≈349 cm\lambda \approx 349\ \text{cm}.

Reading the parameters

The equation is

y(x,t)=3.0 sin⁡ ⁣(36 t+0.018 x+π4),x,y in cm, t in s.y(x,t) = 3.0\,\sin\!\left(36\,t + 0.018\,x + \tfrac{\pi}{4}\right),\qquad x,y\ \text{in cm},\ t\ \text{in s}.

Comparing with the standard travelling-wave form y=Asin⁡(ωt±kx+ϕ0)y = A\sin(\omega t \pm kx + \phi_0):

A=3.0 cm,ω=36 rad/s,k=0.018 rad/cm,ϕ0=π4.A = 3.0\ \text{cm},\quad \omega = 36\ \text{rad/s},\quad k = 0.018\ \text{rad/cm},\quad \phi_0 = \tfrac{\pi}{4}.

A single sinusoid of the combined argument (36t+0.018x+π/4)(36t+0.018x+\pi/4) — not a product sin⁡(kx)cos⁡(ωt)\sin(kx)\cos(\omega t) — so it is a travelling wave, not a stationary one.

(a) Type, speed and direction

The xx and tt terms carry the same (++) sign, so the wave travels in the negative xx-direction. Its speed is

v=ωk=360.018=2000 cm/s=20 m/s.v = \frac{\omega}{k} = \frac{36}{0.018} = 2000\ \text{cm/s} = 20\ \text{m/s}.

(b) Amplitude and frequency

A=3.0 cm,f=ω2π=362π=18π≈5.73 Hz.A = 3.0\ \text{cm},\qquad f = \frac{\omega}{2\pi} = \frac{36}{2\pi} = \frac{18}{\pi} \approx 5.73\ \text{Hz}.

(c) Initial phase at the origin …

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