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Practice Exercise · Q2
Q.

Construct price index number from the following data using

i) Laspeyre's Method and ii) Paasche's method iii) Fisher's Ideal method

CommodityPrice Year 2008Price Year 2010Quantity Year 2008Quantity Year 2010
P2485
Q561210
R451512
S241820
Sikkim CbseNCERTSubjective· 5mImportance★★★★★est
30% · 12/40 Questions
✓ Free question

With the four required sums ∑p1q0=251, ∑p0q0=172, ∑p1q1=220, ∑p0q1=148\sum p_1q_0=251,\ \sum p_0q_0=172,\ \sum p_1q_1=220,\ \sum p_0q_1=148: Laspeyres =145.93=145.93, Paasche =148.65=148.65, Fisher =147.28=147.28.

PL=∑p1q0∑p0q0×100,PP=∑p1q1∑p0q1×100,PF=PL×PPP^{L}=\dfrac{\sum p_1 q_0}{\sum p_0 q_0}\times100,\quad P^{P}=\dfrac{\sum p_1 q_1}{\sum p_0 q_1}\times100,\quad P^{F}=\sqrt{P^{L}\times P^{P}}

p0,p1p_0,p_1 = base (2008) and current (2010) prices; q0,q1q_0,q_1 = base and current quantities.

Working table

Commodityp0p_0p1p_1q0q_0q1q_1p1q0p_1q_0p0q0p_0q_0p1q1p_1q_1p0q1p_0q_1
P248532162010
Q56121072606050
R45151275606048
S24182072368040
Total251172220148
  1. Column sums: ∑p1q0=32+72+75+72=251\sum p_1q_0=32+72+75+72=251; ∑p0q0=16+60+60+36=172\sum p_0q_0=16+60+60+36=172; ∑p1q1=20+60+60+80=220\sum p_1q_1=20+60+60+80=220; ∑p0q1=10+50+48+40=148\sum p_0q_1=10+50+48+40=148.
  2. Laspeyres: PL=251172×100=1.45930×100=145.93P^{L}=\dfrac{251}{172}\times100=1.45930\times100=145.93.
  3. Paasche: PP=220148×100=1.48649×100=148.65P^{P}=\dfrac{220}{148}\times100=1.48649\times100=148.65.
  4. Fisher: PF=PL×PP=145.93×148.65=21 692.5=147.28P^{F}=\sqrt{P^{L}\times P^{P}}=\sqrt{145.93\times148.65}=\sqrt{21\,692.5}=147.28.
  5. Self-check: Fisher (147.28147.28) lies between Laspeyres (145.93145.93) and Paasche (148.65148.65), as a geometric mean must.
✓Final answer

Laspeyres =145.93=145.93, Paasche =148.65=148.65, Fisher's ideal index =147.28=147.28.

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