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Q.In a survey of daily travel time (in minutes) of students to reach their school was recorded as follows: 26, 33, 65, 28, 34, 55, 25, 44, 50, 36, 26, 37, 43, 62, 35, 38, 45, 32, 28, 34 If the mean travelling time is 38.8 minutes and the standard deviation is 11.4 minutes. Convert the travel time of each student into a Z-Score

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Applying Z=x−μσZ=\dfrac{x-\mu}{\sigma} with μ=38.8\mu=38.8 and σ=11.4\sigma=11.4 to each of the 2020 travel times gives the Z-scores tabulated below.

Z=x−μσZ=\dfrac{x-\mu}{\sigma}

where xx = a student’s travel time, μ=38.8\mu=38.8 min (mean), σ=11.4\sigma=11.4 min (standard deviation).

Steps

  1. For each value xx, subtract the mean 38.838.8 and divide by 11.4.11.4.

  2. Worked example (x=65x=65): Z=65−38.811.4=26.211.4=2.30.Z=\dfrac{65-38.8}{11.4}=\dfrac{26.2}{11.4}=2.30.

  3. Worked example (x=25x=25): Z=25−38.811.4=−13.811.4=−1.21.Z=\dfrac{25-38.8}{11.4}=\dfrac{-13.8}{11.4}=-1.21.

  4. Complete table of Z-scores (rounded to 2 dp):

xx (min)x−38.8x-38.8Z=(x−38.8)/11.4Z=(x-38.8)/11.4
26-12.8-1.12
33-5.8-0.51
6526.22.30
28-10.8-0.95
34-4.8-0.42
5516.21.42
25-13.8-1.21
445.20.46
5011.20.98
36-2.8-0.25
26-12.8-1.12
37-1.8-0.16
434.20.37
6223.22.04

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