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Exercise 9.1 · Q12

Q.The order of the differential equation 2x2d2ydx2−3dydx+y=02x^2 \dfrac{d^2 y}{dx^2} - 3 \dfrac{dy}{dx} + y = 0 is (A) 2 (B) 1 (C) 0 (D) not defined

Sikkim CbseNCERTSubjective· 1mImportance★★★★★
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The order of a differential equation is the highest order derivative present. Here, the highest derivative is d2ydx2\frac{d^2 y}{dx^2}, so the order is 2.

The order of a differential equation is one of the first things you check — it tells you the highest derivative that appears in the equation. Think of it like the "depth" of the equation: a first-order equation involves only the first derivative, a second-order involves the second derivative, and so on. No tricks, no hidden conditions — just look for the derivative with the largest exponent of differentiation.

Let’s apply that directly to the given equation.

  1. Identify all derivatives present. The equation is

2x2d2ydx2−3dydx+y=0.2x^2 \frac{d^2 y}{dx^2} - 3 \frac{dy}{dx} + y = 0.

The terms are:

  • d2ydx2\frac{d^2 y}{dx^2} — the second derivative of yy with respect to xx.
  • dydx\frac{dy}{dx} — the first derivative.
  • yy — the function itself (zeroth derivative).
  1. Find the highest order derivative.

    Among these, the derivative with the highest order is d2ydx2\frac{d^2 y}{dx^2}, which is of order 2. No derivative of order 3 or higher appears.

  2. Check for any hidden conditions. …

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