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Worked Examples · Example 19

Q.In a legislative assembly election, a political group hired a public relations firm to promote its candidate in three ways: telephone, house calls, and letters. The cost per contact (in paise) is given in matrix AA as A=[4010050]A = \begin{bmatrix} 40 \\ 100 \\ 50 \end{bmatrix} (Telephone, Housecall, Letter — Cost per contact). The number of contacts of each type made in two cities XX and YY is given by B=[100050050003000100010000]B = \begin{bmatrix} 1000 & 500 & 5000 \\ 3000 & 1000 & 10000 \end{bmatrix} (rows XX, YY; columns Telephone, Housecall, Letter). Find the total amount spent by the group in the two cities XX and YY.

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The city-wise costs are the matrix product BABA. City XX: ₹3,400₹3{,}400; City YY: ₹7,200₹7{,}200; total ₹10,600₹10{,}600.

The cost per contact (paise) is A=[4010050]A=\begin{bmatrix}40\\100\\50\end{bmatrix} and the contact counts are B=[100050050003000100010000]B=\begin{bmatrix}1000&500&5000\\3000&1000&10000\end{bmatrix}. The amount spent per city is BABA:

BA=[1000(40)+500(100)+5000(50)3000(40)+1000(100)+10000(50)]=[40000+50000+250000120000+100000+500000]=[340000720000] paise.BA=\begin{bmatrix}1000(40)+500(100)+5000(50)\\[2pt]3000(40)+1000(100)+10000(50)\end{bmatrix}=\begin{bmatrix}40000+50000+250000\\120000+100000+500000\end{bmatrix}=\begin{bmatrix}340000\\720000\end{bmatrix}\text{ paise}. …

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