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NCERT Exemplar · Q44

Q.If the matrix [0a32b−1c10]\begin{bmatrix}0 & a & 3\\ 2 & b & -1\\ c & 1 & 0\end{bmatrix} is a skew symmetric matrix, find the values of aa, bb and cc.

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A skew-symmetric matrix satisfies AT=−AA^T = -A, which forces all diagonal entries to be zero and pairs of symmetric off-diagonal entries to be negatives of each other. Applying this to the given matrix gives a=−2a = -2, b=0b = 0, and c=−3c = -3.

The key idea is simple: a matrix is skew-symmetric when its transpose equals its negative. That single condition tells you everything about the entries — no guesswork needed.

For any skew-symmetric matrix A=[aij]A = [a_{ij}], the definition AT=−AA^T = -A means:

  • Every diagonal entry must be zero, because aii=−aiia_{ii} = -a_{ii} implies 2aii=02a_{ii} = 0.
  • For off-diagonal entries, aji=−aija_{ji} = -a_{ij} — the entry at (j,i)(j,i) is the negative of the entry at (i,j)(i,j).

Let’s apply this to the given matrix:

A=[0a32b−1c10]A = \begin{bmatrix} 0 & a & 3 \\ 2 & b & -1 \\ c & 1 & 0 \end{bmatrix}

  1. Diagonal entries must be zero.

    The diagonal entries are 00, bb, and 00. The first and third are already zero, so the condition forces b=0b = 0.

  2. Compare symmetric pairs across the diagonal.

    Take the (1,2)(1,2) and (2,1)(2,1) positions:

    a12=aa_{12} = a and a21=2a_{21} = 2. Skew-symmetry requires a21=−a12a_{21} = -a_{12}, so

2=−a⇒a=−2.2 = -a \quad\Rightarrow\quad a = -2.

  1. Now check the (1,3)(1,3) and (3,1)(3,1) pair: a13=3a_{13} = 3 and a31=ca_{31} = c. The condition gives

c=−3.c = -3.

  1. Finally, verify the (2,3)(2,3) and (3,2)(3,2) pair as a consistency check: …

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