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NCERT Exemplar · Q20

Q.The maximum number of equivalence relations on the set A={1,2,3}A = \{1, 2, 3\} are
(A) 1
(B) 2
(C) 3
(D) 5

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An equivalence relation corresponds to a partition of the set. The set {1,2,3}\{1,2,3\} can be partitioned in exactly 5 ways, so the maximum number of equivalence relations is 5.

The key idea: equivalence relations and partitions are the same thing. Every equivalence relation on a set splits the set into disjoint, non-empty subsets called equivalence classes. Conversely, every partition gives you an equivalence relation (two elements are related if they belong to the same block). So counting equivalence relations is exactly counting partitions.

For a 3-element set, we can systematically list all possible ways to group the elements.

  1. One block (all elements together)

    Only one partition: {1,2,3}\{1,2,3\}. This gives the equivalence relation where every element is related to every other. That's 1 relation.

  2. Two blocks (one block of size 2, one block of size 1)

    We choose which two elements go together. The possibilities:

    • {1,2}\{1,2\} and {3}\{3\}
    • {1,3}\{1,3\} and {2}\{2\}
    • {2,3}\{2,3\} and {1}\{1\} That's 3 partitions, hence 3 relations.
  3. Three blocks (each element alone)

    Only one partition: {1},{2},{3}\{1\}, \{2\}, \{3\}. This is the equality relation (each element related only to itself). That's 1 relation.

Adding them up: 1+3+1=51 + 3 + 1 = 5. …

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