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Exercises · 13.16

Q.Write nuclear reaction equations for

(i) α\alpha-decay of 88226Ra^{226}_{88}\text{Ra}
(ii) α\alpha-decay of 94242Pu^{242}_{94}\text{Pu}
(iii) β−\beta^{-}-decay of 1532P^{32}_{15}\text{P}
(iv) β−\beta^{-}-decay of 83210Bi^{210}_{83}\text{Bi}
(v) β+\beta^{+}-decay of 611C^{11}_{6}\text{C}
(vi) β+\beta^{+}-decay of 4397Tc^{97}_{43}\text{Tc}
(vii) Electron capture of 54120Xe^{120}_{54}\text{Xe}
Sikkim CbseNCERTSubjective· 3mImportance★★★★★est
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Balance mass number AA and atomic number ZZ on both sides for each decay type; the seven equations are listed below with the physics of each mode explained.

(i) α\alpha-decay of 88226Ra^{226}_{88}\text{Ra}

An alpha particle (24He^4_2\text{He} nucleus) is emitted, so AA drops by 4 and ZZ by 2:

88226Ra→86222Rn+24He^{226}_{88}\text{Ra} \rightarrow {}^{222}_{86}\text{Rn} + {}^{4}_{2}\text{He}

(ii) α\alpha-decay of 94242Pu^{242}_{94}\text{Pu}

94242Pu→92238U+24He^{242}_{94}\text{Pu} \rightarrow {}^{238}_{92}\text{U} + {}^{4}_{2}\text{He}

(iii) β−\beta^{-}-decay of 1532P^{32}_{15}\text{P}

A neutron inside the nucleus converts to a proton, emitting an electron and an antineutrino; AA is unchanged, ZZ increases by 1:

1532P→1632S+e−+νˉ^{32}_{15}\text{P} \rightarrow {}^{32}_{16}\text{S} + e^{-} + \bar{\nu}

(iv) β−\beta^{-}-decay of 83210Bi^{210}_{83}\text{Bi}

83210Bi→84210Po+e−+νˉ^{210}_{83}\text{Bi} \rightarrow {}^{210}_{84}\text{Po} + e^{-} + \bar{\nu}

(v) β+\beta^{+}-decay of 611C^{11}_{6}\text{C}

Here a proton converts to a neutron, emitting a positron and a neutrino; ZZ decreases by 1:

611C→511B+e++ν^{11}_{6}\text{C} \rightarrow {}^{11}_{5}\text{B} + e^{+} + \nu

(vi) β+\beta^{+}-decay of 4397Tc^{97}_{43}\text{Tc}

4397Tc→4297Mo+e++ν^{97}_{43}\text{Tc} \rightarrow {}^{97}_{42}\text{Mo} + e^{+} + \nu

(vii) Electron capture of 54120Xe^{120}_{54}\text{Xe} …

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