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Question 27 of 35

Q.The total cost function yy for xx units is given by y=3x(x+7x+5)+5y = 3x\left(\dfrac{x + 7}{x + 5}\right) + 5. Show that the Marginal Cost [MC] decreases continuously as the output (x)(x) increases.

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Commerce Board 2023Subjective· 3mImportance★★★★★
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y=3xx+7x+5+5y = 3x\dfrac{x+7}{x+5} + 5 gives MC=3+30(x+5)2MC = 3 + \dfrac{30}{(x+5)^2}; since d(MC)dx=−60(x+5)3<0\dfrac{d(MC)}{dx} = -\dfrac{60}{(x+5)^3} < 0, MC falls steadily as xx rises.

Step 1 — Total cost.

y=3x(x+7)x+5+5=3x2+21xx+5+5.y = \frac{3x(x+7)}{x+5} + 5 = \frac{3x^2 + 21x}{x+5} + 5.

Step 2 — Differentiate (quotient rule) to get MCMC. With u=3x2+21x, v=x+5u = 3x^2+21x,\ v = x+5:

MC=dydx=(6x+21)(x+5)−(3x2+21x)(x+5)2=3x2+30x+105(x+5)2.MC = \frac{dy}{dx} = \frac{(6x+21)(x+5) - (3x^2+21x)}{(x+5)^2} = \frac{3x^2 + 30x + 105}{(x+5)^2}.

Step 3 — Simplify by writing the numerator about (x+5)(x+5). Put t=x+5t = x+5; then 3x2+30x+105=3t2+303x^2+30x+105 = 3t^2 + 30, so

MC=3t2+30t2=3+30(x+5)2.MC = \frac{3t^2 + 30}{t^2} = 3 + \frac{30}{(x+5)^2}.

Step 4 — Show MCMC decreases. Differentiate MCMC: …

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