Skip to content
Worked Examples · Example 3

Q.Find the amount of each equal annual instalment needed to repay a loan of ₹1,00,000 in 5 equal yearly instalments at 10% per annum compound interest. [Given (1.1)−5=0.6209(1.1)^{-5} = 0.6209]

Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
30% · 9/30 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1 — Recognise the loan amount as a present value. The ₹1,00,000 sanctioned today must equal the present value of the 5 future instalments, so V=1,00,000V=1{,}00{,}000, i=0.10i=0.10, n=5n=5.

Step 2 — Rearrange the present value formula for PP.

V=P[1−(1+i)−ni]  ⇒  P=V⋅i1−(1+i)−nV = P\left[\dfrac{1-(1+i)^{-n}}{i}\right] \;\Rightarrow\; P = \dfrac{V\cdot i}{1-(1+i)^{-n}}

Step 3 — Substitute the known values.

P=1,00,000×0.101−(1.1)−5=10,0001−0.6209=10,0000.3791≈26,378P = \dfrac{1{,}00{,}000\times0.10}{1-(1.1)^{-5}} = \dfrac{10{,}000}{1-0.6209} = \dfrac{10{,}000}{0.3791} \approx 26{,}378 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.