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Exercise 5.2 · Q3

Q.Write the nthn^{th} term of the following sequences.

(i) 2,2,4,4,6,6,…2,2,4,4,6,6,\ldots
(ii) 12,23,34,45,56,…\dfrac12,\dfrac23,\dfrac34,\dfrac45,\dfrac56,\ldots
(iii) 12,34,56,78,910,…\dfrac12,\dfrac34,\dfrac56,\dfrac78,\dfrac9{10},\ldots
(iv) 6,10,4,12,2,14,0,16,−2,…6,10,4,12,2,14,0,16,-2,\ldots
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For each listed sequence, look for the underlying pattern in the index — a repeated-pair rule, a numerator/denominator pattern, or two interleaved arithmetic progressions on alternating positions.

Step 1. (i) 2,2,4,4,6,6,…2,2,4,4,6,6,\ldots. This is exactly the sequence from Exercise 5.2 Q2(i): each even number is repeated twice. So an=n+1a_n=n+1 when nn is odd (giving the even number n+1n+1), and an=na_n=n when nn is even (already even). an={n+1n oddnn evena_n=\begin{cases}n+1 & n\text{ odd}\\ n & n\text{ even}\end{cases}.

Step 2. (ii) 12,23,34,45,56,…\dfrac12,\dfrac23,\dfrac34,\dfrac45,\dfrac56,\ldots. Numerator =n=n, denominator =n+1=n+1: an=nn+1a_n=\dfrac n{n+1}.

Step 3. (iii) 12,34,56,78,910,…\dfrac12,\dfrac34,\dfrac56,\dfrac78,\dfrac9{10},\ldots. Numerator is the odd number 2n−12n-1, denominator is the even number 2n2n: an=2n−12na_n=\dfrac{2n-1}{2n}.

Step 4. (iv) 6,10,4,12,2,14,0,16,−2,…6,10,4,12,2,14,0,16,-2,\ldots. The odd-position terms (1st,3rd,5th,…1^{st},3^{rd},5^{th},\ldots) are 6,4,2,0,−2,…6,4,2,0,-2,\ldots — an AP with first term 66, common difference −2-2; for n=2k−1n=2k-1, value =6−2(k−1)=8−2k=7−n=6-2(k-1)=8-2k=7-n (checking n=1→6n=1\to6, n=3→4n=3\to4, etc.). The even-position terms (2nd,4th,…2^{nd},4^{th},\ldots) are 10,12,14,16,…10,12,14,16,\ldots — an AP with first term 1010, common difference 22; for n=2kn=2k, value =10+2(k−1)=8+2k=n+8=10+2(k-1)=8+2k=n+8 (checking n=2→10n=2\to10, n=4→12n=4\to12, etc.).

an={7−nn oddn+8n evena_n = \begin{cases} 7-n & n \text{ odd} \\ n+8 & n \text{ even}\end{cases}

✓Final answer

  1. an={n+1n oddnn evena_n=\begin{cases}n+1 & n\text{ odd}\\ n & n\text{ even}\end{cases};
  2. an=nn+1a_n=\dfrac n{n+1};
  3. an=2n−12na_n=\dfrac{2n-1}{2n};
  4. an={7−nn oddn+8n evena_n=\begin{cases}7-n & n\text{ odd}\\ n+8 & n\text{ even}\end{cases}

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