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Exercise 5.5 · Q14

Q.The nthn^{th} term of the sequence 12,34,78,1516,⋯\dfrac12,\dfrac34,\dfrac78,\dfrac{15}{16},\cdots is

(1) 2n−n−12^n-n-1
(2) 1−2−n1-2^{-n}
(3) 2−n+n−12^{-n}+n-1
(4) 2n−12^{n-1}
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Notice each term's numerator is one less than its denominator (both powers of 2), and simplify.

Step 1. Spot the pattern. 12,34,78,1516,…\dfrac12,\dfrac34,\dfrac78,\dfrac{15}{16},\ldots: denominators are 2n2^n, numerators are 2n−12^n-1. …

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