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Question 94 of 95

Q.The HM of two positive numbers whose AM and GM are 16, 8 respectively is:

(a) 5
(b) 10
(c) 4
(d) 6
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2026MCQ· 1mImportance★★★★★
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For two positive numbers, GM2=AM×HMGM^2=AM\times HM, so HM=GM2/AM=64/16=4HM=GM^2/AM=64/16=4.

For two positive numbers a,ba,b: AM=a+b2AM=\dfrac{a+b}{2}, GM=abGM=\sqrt{ab}, HM=2aba+bHM=\dfrac{2ab}{a+b}.

A standard identity relates them: AM×HM=a+b2×2aba+b=ab=GM2AM\times HM=\dfrac{a+b}{2}\times\dfrac{2ab}{a+b}=ab=GM^2.

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