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Exercise 4.1 · Q15

Q.Evaluate n!r!(n−r)!\dfrac{n!}{r!(n-r)!} when

(i) n=6,r=2n=6, r=2
(ii) n=10,r=3n=10, r=3
(iii) For any nn with r=2r=2.
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n!r!(n−r)!\dfrac{n!}{r!(n-r)!} is the combinations formula nCr^nC_r; cancel the larger factorial tail first.

Step 1. (i) n=6,r=2n=6,r=2: 6!2! 4!=6×52=15\dfrac{6!}{2!\,4!}=\dfrac{6\times5}{2}=15.

Step 2. (ii) n=10,r=3n=10,r=3: 10!3! 7!=10×9×86=120\dfrac{10!}{3!\,7!}=\dfrac{10\times9\times8}{6}=120. …

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