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Question 119 of 134

Q.If n∈Nn \in N, then 72n+33n−3⋅3n−17^{2n} + 3^{3n-3}\cdot 3^{n-1} is always divisible by:

(a) 45
(b) 25
(c) 55
(d) 35
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2023MCQ· 1mImportance★★★★★
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This is the well-known textbook induction result that 72n+23n−3⋅3n−17^{2n}+2^{3n-3}\cdot 3^{n-1} is always divisible by 25 for every natural number nn.

Check the base case n=1n=1: 72+20⋅30=49+1=50=25×27^2 + 2^{0}\cdot 3^{0} = 49+1 = 50 = 25\times 2. Divisible by 25.

Check n=2n=2: 74+23⋅31=2401+8×3=2401+24=2425=25×977^4 + 2^{3}\cdot 3^{1} = 2401 + 8\times 3 = 2401+24 = 2425 = 25\times 97. Divisible by 25.

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