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Mathematics · Ch 10 — Differential Calculus – Differentiability and Methods of Differentiation

The tangent line problem

10.2.1

The tangent line problem

For a circle, "the tangent at PP" has a clean, purely geometric meaning: it is the line through PP perpendicular to the radius at PP (Fig. 10.1). For a general curve, that definition breaks down entirely — there is no "radius" to be perpendicular to. Nor does "touches but does not cross" work in general: it holds for some curves (Fig. 10.2) but fails for others where a genuine tangent line still crosses the curve at the point of tangency (Fig. 10.3); and "touches at exactly one point" works for a circle but fails for most other curves (Fig. 10.4), which a tangent line may meet again elsewhere.

The way out is to stop trying to define the tangent line directly and instead define it as a limit of secant lines. Let P(x0,f(x0))P(x_0, f(x_0)) be the point of tangency and let Q(x0+Δx, f(x0+Δx))Q(x_0+\Delta x,\ f(x_0+\Delta x)) be a second point on the curve y=f(x)y=f(x). The line through PP and QQ is a secant line, and (from the two-point slope formula) its slope is the difference quotient

msec=f(x0+Δx)−f(x0)(x0+Δx)−x0=f(x0+Δx)−f(x0)Δx=ΔyΔx,m_{\text{sec}} = \frac{f(x_0+\Delta x)-f(x_0)}{(x_0+\Delta x)-x_0} = \frac{f(x_0+\Delta x)-f(x_0)}{\Delta x} = \frac{\Delta y}{\Delta x},

where Δx\Delta x is the increment in xx and Δy=f(x0+Δx)−f(x0)\Delta y = f(x_0+\Delta x)-f(x_0) is the corresponding change in yy. The beauty of this construction is that choosing QQ closer and closer to PP (i.e. letting Δx→0\Delta x \to 0) makes msecm_{\text{sec}} a better and better approximation to the true slope of the tangent at PP — turning an unsolved geometric question into a limit computation.

Worked illustration (the book's own numbers). Take f(x)=x2f(x)=x^2 and P=(1,1)P=(1,1). With Δx=0.1\Delta x = 0.1: f(1.1)=1.21f(1.1) = 1.21, so Δy=1.21−1=0.21\Delta y = 1.21-1=0.21 and msec=0.21/0.1=2.1m_{\text{sec}} = 0.21/0.1 = 2.1. Tabulating Δy/Δx\Delta y/\Delta x for Δx=±0.1,±0.01,±0.001\Delta x = \pm0.1, \pm0.01, \pm0.001 gives 2.1,2.01,2.0012.1, 2.01, 2.001 from the right and 1.9,1.99,1.9991.9, 1.99, 1.999 from the left — both sequences squeezing toward 22. Formally, lim⁡Δx→0−Δy/Δx=2=lim⁡Δx→0+Δy/Δx\lim_{\Delta x\to 0^-}\Delta y/\Delta x = 2 = \lim_{\Delta x\to0^+}\Delta y/\Delta x, so lim⁡Δx→0Δy/Δx=2\lim_{\Delta x\to0}\Delta y/\Delta x = 2: the tangent to y=x2y=x^2 at (1,1)(1,1) has slope mtan⁡=2m_{\tan}=2.

This motivates:

Definition 10.1 (Tangent line with slope mm). Let ff be defined on an open interval containing x0x_0. If

mtan⁡=lim⁡Δx→0f(x0+Δx)−f(x0)Δx=lim⁡Δx→0ΔyΔxm_{\tan} = \lim_{\Delta x\to 0}\frac{f(x_0+\Delta x)-f(x_0)}{\Delta x} = \lim_{\Delta x\to0}\frac{\Delta y}{\Delta x}

exists, then the line through (x0,f(x0))(x_0,f(x_0)) with slope mtan⁡m_{\tan} is the tangent line to the graph of ff at (x0,f(x0))(x_0,f(x_0)); this same number is also called the slope of the curve at that point.

Because a point together with a slope determines exactly one line, the definition guarantees that if a tangent line exists at a point, it is unique. …