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Exercise 9.3 · Q10

Q.A tank contains 5000 litres of pure water. Brine (very salty water) that contains 30 grams of salt per litre of water is pumped into the tank at a rate of 25 litres per minute. The concentration of salt water after tt minutes (in grams per litre) is
[!FORMULA] C(t)=30t200+tC(t)=\dfrac{30t}{200+t}
What happens to the concentration as t→∞t\to\infty?

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As t→∞t\to\infty, divide by tt (the highest power present) to see what constant value the concentration settles toward.

Step 1. Write down the model.

C(t)=30t200+tC(t)=\frac{30t}{200+t}

Step 2. Divide numerator and denominator by tt (valid for t>0t>0):

C(t)=30t/t(200+t)/t=30200t+1C(t)=\frac{30t/t}{(200+t)/t}=\frac{30}{\dfrac{200}t+1}

Step 3. Let t→∞t\to\infty. Since 200200 is a fixed constant, 200t→0\dfrac{200}t\to0:

C(t) ⟶ 300+1=30C(t)\ \longrightarrow\ \frac{30}{0+1}=30 …

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