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Exercise 12.4 · Q5

Q.An advertising executive is studying the television viewing habits of married men and women during prime time hours. Based on past viewing records he has determined that during prime time, wives are watching television 60% of the time. It has also been determined that when the wife is watching television, 40% of the time the husband is also watching. When the wife is not watching television, 30% of the time the husband is watching television. Find the probability that

(i) the husband is watching television during the prime time hours
(ii) if the husband is watching television, the wife is also watching television.
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
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Step 1. Given. P(wife watches)=0.6P(\text{wife watches})=0.6, so P(wife not watching)=0.4P(\text{wife not watching})=0.4. P(husband/wife watches)=0.4P(\text{husband}/\text{wife watches})=0.4; P(husband/wife not watching)=0.3P(\text{husband}/\text{wife not watching})=0.3.

Step 2. Part (i) -- Total Probability. P(husband watches)=P(wife)P(husband/wife)+P(wife‾)P(husband/wife‾)=(0.6)(0.4)+(0.4)(0.3)=0.24+0.12=0.36P(\text{husband watches})=P(\text{wife})P(\text{husband}/\text{wife})+P(\overline{\text{wife}})P(\text{husband}/\overline{\text{wife}})=(0.6)(0.4)+(0.4)(0.3)=0.24+0.12=0.36. …

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