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Mathematics · Ch 7 — Matrices and Determinants

Relation between a Determinant and its Cofactor Determinant

7.3.5

Relation between a Determinant and its Cofactor Determinant

Let ∣A∣=∣a1b1c1a2b2c2a3b3c3∣|A|=\begin{vmatrix}a_1&b_1&c_1\\a_2&b_2&c_2\\a_3&b_3&c_3\end{vmatrix}, and let A1,B1,C1,…,A3,B3,C3A_1,B_1,C_1,\ldots,A_3,B_3,C_3 be the cofactors of a1,b1,c1,…,a3,b3,c3a_1,b_1,c_1,\ldots,a_3,b_3,c_3 respectively.

Two companion facts about cofactors:

  1. Expanding a row (or column) against its own cofactors reproduces the determinant: a1A1+b1B1+c1C1=∣A∣a_1A_1+b_1B_1+c_1C_1=|A| (this is just Laplace expansion, restated).
  2. Expanding a row (or column) against the cofactors of a different row (column) always gives 00: a1A2+b1B2+c1C2=0a_1A_2+b_1B_2+c_1C_2=0, and likewise for every other mismatched pairing (Note 7.12).

Now form the cofactor determinant ∣A1B1C1A2B2C2A3B3C3∣\begin{vmatrix}A_1&B_1&C_1\\A_2&B_2&C_2\\A_3&B_3&C_3\end{vmatrix} and multiply it (row-by-row, §7.3.4) with ∣A∣|A| itself. Every diagonal product comes out ∣A∣|A| (fact 1), and every off-diagonal product comes out 00 (fact 2), so the product determinant is simply ∣A∣3|A|^3 (the determinant of a diagonal matrix with ∣A∣|A| repeated three times). Since the product of two determinants equals the determinant of the matrix product,

∣A∣×∣A1B1C1A2B2C2A3B3C3∣=∣A∣3.|A|\times\begin{vmatrix}A_1&B_1&C_1\\A_2&B_2&C_2\\A_3&B_3&C_3\end{vmatrix}=|A|^3. …