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Exercise 1.2 · Q3

Q.Let A={a,b,c}A=\{a,b,c\} and R={(a,a),(b,b),(a,c)}R=\{(a,a),(b,b),(a,c)\}. Write down the minimum number of ordered pairs to be included to RR to make it

(i) reflexive
(ii) symmetric
(iii) transitive
(iv) equivalence
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✓ Free question

A={a,b,c}A=\{a,b,c\}, R={(a,a),(b,b),(a,c)}R=\{(a,a),(b,b),(a,c)\}.

Step 1 (i) reflexive. Need (a,a),(b,b),(c,c)(a,a),(b,b),(c,c). Missing only (c,c)(c,c) -- 1 pair.

Step 2 (ii) symmetric. (a,c)(a,c) needs reverse (c,a)(c,a) -- 1 pair.

Step 3 (iii) transitive. As in Q2, the only chain (a,a)&(a,c)→(a,c)(a,a)\&(a,c)\to(a,c) is already satisfied; no other chains exist. 0 pairs needed.

Step 4 (iv) equivalence. Add (c,c)(c,c) and (c,a)(c,a): R′={(a,a),(b,b),(a,c),(c,c),(c,a)}R'=\{(a,a),(b,b),(a,c),(c,c),(c,a)\}. Check transitivity: (a,c)&(c,a)→(a,a)(a,c)\&(c,a)\to(a,a) present; (c,a)&(a,c)→(c,c)(c,a)\&(a,c)\to(c,c) present; (a,c)&(c,c)→(a,c)(a,c)\&(c,c)\to(a,c) present; (c,a)&(a,a)→(c,a)(c,a)\&(a,a)\to(c,a) present -- transitive, no more pairs needed. Total: 2 pairs ((c,c),(c,a)(c,c),(c,a)).

✓Final answer

  1. {(c,c)}\{(c,c)\} -- 1 pair.
  2. {(c,a)}\{(c,a)\} -- 1 pair.
  3. none needed.
  4. {(c,c),(c,a)}\{(c,c),(c,a)\} -- 2 pairs.

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